Question

An object falls from a high building. Ignoring air resistance, what will its velocity be after 6 seconds of falling

Answer 1

Explanation:

Vf=Vi+at

reference frame,take down as positive in y- axis

Data

Vi=0m/s

Vf=?

a=g(9.8m/s2)

t=6s

Vf=0+9.8m/s2*6s

Vf=58.8m/s

Answer 2

Answer:

$u = 0 \\ t = 6 \: s \\ g = 10 \: m {s}^{ - 2} \\ from \: first \: equation \: of \: motion \\ v = u + gt \\ v = 0 + (10 \times 6) \\ v = 60 \: m {s}^{ - 1}$