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Rzqust [24]
3 years ago
13

Consider the reaction below.

Chemistry
2 answers:
SpyIntel [72]3 years ago
3 0
Water is an amphoteric compound. This means it could be a base or an acid, depending on the substance it is to be reacted with. In this case, water is a base because HF is an acid. Now, if the reactant is an acid, its form after the reaction is called the conjugate pair. Since HF became F⁻, <em>the acid-conjugate base pair is: HF and F⁻.</em>
Alex Ar [27]3 years ago
3 0

Option B: HF and F-

Your Welcome

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Many organisms in an ecosystem copete with each other for resources. What might different species of trees in a forest ecosystem
sineoko [7]
Territory and energy sources
4 0
3 years ago
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Astroturf is a durable artificial surface used to cover athletic fields. A soccer field 0.06214- mile-long by 253 ft wide is cov
love history [14]

Answer:

The weight of the Astroturf is 179,684.31 Newtons.

Explanation:

Length of a soccer field = 0.06214 mile = 328.0992 feet

(1 mile = 5280 feet)

Breadth of a soccer field  = 253 feet

Length of a Astroturf which soccer field is to be covered, l = 328.0992 feet

Breadth of a Astroturf which soccer field is to be covered ,b = 253 feet

Thickness of a Astroturf with which soccer field is to be covered = h

h = ½ inch = 0.5 inch = 0.041665 feet

(1 inches = 0.08333 feet)

Volume of the Astroturf ,V= l × b × h

V=328.0992 ft\times 253 ft\times 0.041665 ft=3,458.574 ft^3

Mass of the Astroturf = m

Density of the Astroturf = d = 187 oz/ft^3

d=\frac{m}{V}

m=d\times V= 187 oz/ft^3\times 3,458.574 ft^3=646,753.35 oz

1 oz = 0.0283495 kg

m=646,743.35 oz=646,743.35\times 0.0283495 kg=18,335.13 kg

Weight of the Astroturf = W

W = mg

=W=18,335.13 kg\times 9.8 m/s^2=179,684.31 N

The weight of the Astroturf is 179,684.31 Newtons.

8 0
3 years ago
Are usually solid shiny and conductive object
crimeas [40]
If the solid is a metal, yes. Most solids on the periodic table are metals
8 0
3 years ago
The second order reaction A → Products takes 13.5 s for the concentration of A to decrease from 0.740 M to 0.319 M. What is the
Ivanshal [37]

The rate constant of the second order reaction is 0.137 M-1s-1.

<h3>What is the rate constant?</h3>

For the second order reaction we can write;

1/[A] = kt + 1/[A]o

[A]o = initial concentration

[A] = final concentration

k = rate constant

t = time

Now;

1/0.319 = 13.5k + 1/ 0.740

1/0.319 - 1/0.740 = 13.5k

3.13 - 1.35 = 13k

k = 3.13 - 1.35/13

k = 0.137 M-1s-1

Learn more about second order reaction:brainly.com/question/12446045

#SPJ1

8 0
2 years ago
In a similar way to oxidation-reduction reactions, half-reactions can be written for electrochemical reactions.
kirza4 [7]

the answer to this question would be true just thought u should know lol xd



7 0
3 years ago
Read 2 more answers
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