Answer:
C₅H₁₀O₄
Explanation:
The empirical formula is the simplest whole-number ratio of atoms in a compound.
The ratio of atoms is the same as the ratio of moles.
So, our job is to calculate the molar ratio of C:H:O.
Assume 100 g of deoxyribose.
1. Calculate the mass of each element.
Then we have 44.8 g C, 7.5 g H, and 47.7 g O.
2. Calculate the moles of each element

3. Calculate the molar ratio of the elements
Divide each number by the smallest number of moles
C:H:O = 3.730:7.44:2.981 = 1.251:2.50:1 = 5.005:9.98:4 ≈ 5:10:4
4. Write the empirical formula
EF = C₅H₁₀O₄
20 B203(s) + 12180 HF(l) = 4060 BF3(g) + 609 H20(l)
<h2>Double displacement reaction:</h2>
A double displacement reaction is a type of chemical reaction where two compounds react, and positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds or products.
<h3>For example:</h3>
Na2S+2HCl→2NaCl+H2S
hope it's helpful :)
The answer is 3 It is a body of knowledge gained using inquiry and experimentation. Hope this helped!
The structure of this oligopeptide is attached:
It consists of arginine - alanine - phenylalanine and leucine
From the picture we can see that N terminus charge is +1
Also Arginine is considered as basic amino acid with charge +1
C terminus charge is -1
At pH = 8, the whose pKa are less than pH will be deprotonated and the net charge will be +1
So the net charge of this oligopeptide is +1 at pH = 8