600,000 mm if im not mistaken.
Answer:
pH = 13.1
Explanation:
Hello there!
In this case, according to the given information, we can set up the following equation:

Thus, since there is 1:1 mole ratio of HCl to KOH, we can find the reacting moles as follows:

Thus, since there are less moles of HCl, we calculate the remaining moles of KOH as follows:

And the resulting concentration of KOH and OH ions as this is a strong base:
![[KOH]=[OH^-]=\frac{0.00576mol}{0.012L+0.032L}=0.131M](https://tex.z-dn.net/?f=%5BKOH%5D%3D%5BOH%5E-%5D%3D%5Cfrac%7B0.00576mol%7D%7B0.012L%2B0.032L%7D%3D0.131M)
And the resulting pH is:

Regards!
Answer:
moles
Explanation:
The reaction equation is given as:
4NH₃ + 5O₂ → 4NO + 6H₂O
The number of moles of O₂ that completely reacted is given as 1 mole
To solve this problem, we are going to use a stoichiometric approach from the balanced reaction equation:
5 moles of O₂ will react completely to produce 4 moles of NO
1 mole of O₂ will therefore react to produce x mole of NO
5x = 4
x =
moles of NO
C3H6 and CH4
The empirical number is found by looking at the ratio of the numbers. For example, H20 and H402 have the same empirical formula because the ratio remained similar. 2 H to 1 O.
Answer:
12.89 moles
Explanation:
Before we solve the question, we have to balance the equation of the reaction first. The balanced reaction will be:
2 NO + 2 H2→ N2 + 2 H2O
There are 180.5g of N2 produced, the number of produced in moles will be: 180.5g / (28g/mol)= 6.446 moles
The coefficient of H2 is two and the coefficient of N2 is one. Mean that we need two moles of H2 for every one mole of N2 produced. The number of H2 reacted will be: 2/1 * 6.446 moles = 12.89 moles