Answer:
The correct option is D
Explanation:
Normally, beta-oxidation of fatty acid occurs in the mitchondrial matrix, however, when the fatty acid chains are too long, the beta-oxidation occurs in the peroxisomes <u>where the oxidation is not attached to ATP synthesis but rather transferred (i.e high energy electrons are transferred) to O₂ to form hydrogen peroxide</u> (H₂O₂). This is the major difference between the beta-oxidation that occurs in the peroxisomes to that which occurs in the mitochondria.
The number of protons in the nucleus of the atom is equal to the atomic number (Z). The number of electrons in a neutral atom is equal to the number of protons. The mass number of the atom (M) is equal to the sum of the number of protons and neutrons in the nucleus.
Superscript o subscript negative 1 e.
Explanation:
The nuclear reactions is of 2 types, one is nuclear fusion and the other one is nuclear fission.
Nuclear fusion is nothing but the combining of 2 nuclei with an emission of energy along with an electron, proton or beta particle.
Nuclear fission is the break down of a nucleus into 2 or more nuclei along with an electron, proton or beta particle.
And the reaction is,
₅₆B¹²⁴ ₅₅C¹²⁴ + ₋₁e⁰
So the blank was filled by means of a beta particle.
Answer:
Ne
Explanation:
Atomic number of Ne is 10.
Electronic configuration of Ne:
Octet of Ne is complete . Element having complete octet are stable and behave ideal gas.
and 
are reactive and hence, does not behave as ideal gas.
Explanation:
As per the Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
Hence, according to this law the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
..........(1)
..............(2)
The final reaction is as follows:
.............(3)
Therefore, adding (1) and (2) we get the final equation (3) and value of 
at 298 K will be as follows.
= 
+ 
= -314 kJ + (-80) kJ
= -394 kJ
Thus, we can conclude that 
at 298 K for the given process is -394 kJ.
