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Vadim26 [7]
3 years ago
8

Two wheels have the same mass and radius of 4.2 kg and 0.42 m, respectively. One has (a) the shape of a hoop and the other (b) t

he shape of a solid disk. The wheels start from rest and have a constant angular acceleration with respect to a rotational axis that is perpendicular to the plane of the wheel at its center. Each turns through an angle of 14 rad in 8.3 s. Find the net external torque that acts on each wheel.
Physics
1 answer:
andrew-mc [135]3 years ago
4 0

Answer:

τsolid = 0.15 N•m

τhoop = 0.30 N•m

Explanation:

θ = ½αt²

α = 2θ/t² = 2(14)/8.3² = 0.406445 rad/s²

Solid disk I = ½mr² = ½(4.2)0.42² = 0.37044 kg•m²

τ = Iα = 0.37044(0.406445) = 0.150563... N•m

Hoop disk I = mr² = (4.2)0.42² = 0.74088 kg•m²

τ = Iα = 0.74088(0.406445) = 0.301127... N•m

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Answer:

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Explanation:

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  • 0.916 km due east is an horizontal direction and cane be seen as  direction towards the negative side of X-axis.
  • 0.928 km due south is a vertical direction and can be seen as a direction towards the negative side of Y-axis.
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First of all. We need to sum all the X components and all the Y componets.

∑Sx = Ax -0.916 ⇒  ∑Sx = [tex]3.52cos(49.7) - 0.916

∑Sx = 1.361 km

∑Sy = Ay - 0.918 ⇒ ∑Sy = 3.52sin(49.7) - 0.918

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The total displacement is calculated using Pythagoeran therorem:

S_{total} =\sqrt{Sx^{2}+ Sy^{2} } ⇒

S_{total} = 2.230 km

With displacement calculated, we can find the average speed as follows:

V = S/t  ⇒  V = \frac{2.230}{1.750}

V = 1.274\frac{km}{h}

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