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otez555 [7]
3 years ago
12

A golfer and her caddy see lightning nearby. the golfer is about to take his shot with a metal club, while her caddy is holding

a plastic handled umbrella. which person is at greater risk? Explain why?
Engineering
1 answer:
Sveta_85 [38]3 years ago
7 0

Answer:

The golfer is at greater risk.

Explanation:

The golfer is holding a metal club. Metal is a good conductor for electricity (lightning), meaning electrons can pass through easily. Her caddy is at lesser risk because she is holding a plastic handled umbrella. Plastic is an insulator, which does not easily allow the movement of electrons to pass.

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Write a function called largest3 which takes 3 numbers as parameters and returns the largest of the 3. Write a program which tak
tamaranim1 [39]

Answer:

The solution code is written in Python.

  1. def largest3(num1, num2, num3):
  2.    largest = num1
  3.    if(largest < num2):
  4.        largest = num2
  5.    
  6.    if(largest < num3):
  7.        largest = num3
  8.    
  9.    return largest
  10. first_num = int(input("Enter first number: "))
  11. second_num = int(input("Enter second number: "))
  12. third_num = int(input("Enter third number: "))
  13. largest_number = largest3(first_num, second_num, third_num)
  14. print("The largest number is " + str(largest_number))

Explanation:

<u>Create function largest3</u>

  • Firstly, we can create a function <em>largest3 </em>which take 3 numbers (<em>num1, num2, num3</em>) as input. (Line 1).
  • Please note Python uses keyword <em>def </em>to denote a function. The code from Line 2 - 10 are function body of <em>largest3</em>.
  • Within the function body, create a variable,<em> largest</em>, to store the largest number. In the first beginning, just tentatively assign<em> num1 </em>to<em> largest</em>. (Line 2)
  • Next, proceed to check if the current "<em>largest</em>" value smaller than the<em> num2 </em>(Line 4). If so, replace the original value of largest variable with <em>num2</em> (Line 5).
  • Repeat the similar comparison procedure to<em> </em><em>num3</em> (Line 7-8)
  • At the end, return the final value of "<em>largest</em>" as output

<u>Get User Input</u>

  • Prompt use input for three numbers (Line 13 -15) using Python built-in <em>input</em> function.
  • Please note the input parts of codes is done outside of the function <em>largest3</em>.

<u>Call function to get largest number and display</u>

  • We can simply call the function<em> largest </em>by writing the function name <em>largest</em> and passing the three user input into the parenthesis as arguments. (Line 17)
  • The function <em>largest </em>will operate on the three arguments and return the output to the variable <em>largest_number</em>.
  • Lastly, print the output using Python built-in <em>print</em> function. (Line 18)
  • Please note the output parts of codes is also done outside of the function<em> largest3</em>.
6 0
3 years ago
1) When you invest in stock, what are you doing?
statuscvo [17]

<u>Explanation:</u>

1) When we invest in stock it means we are investing in long term investment. It includes risk factor also.

2) We can make money from stocks by retaining them for a long period and selling them when their price rises.

3) dividends are paid out of distributable profits. Some companies provide dividends regularly which act as a regular source of income for investors.

4) Capital gain is the benefit obtained on selling a capital asset and if we face loss on selling the capital asset it results in capital loss. Capital assets are like stock, bonds, properties, etc.

7 0
3 years ago
A levee will be constructed to provide some flood protection for a residential area. The residences are willing to accept a one-
777dan777 [17]

Answer:

1709.07 ft^3/s

Explanation:

Annual peak streamflow = Log10(Q [ft^3/s] )

mean = 1.835

standard deviation = 0.65

Probability of levee been overtopped in the next 15 years = 1/5

<u>Determine the design flow ins ft^3/s </u>

P₁₅ = 1 - ( q )^15 = 1 - ( 1 - 1/T )^15 = 0.2

                         ∴  T = 67.72 years

Q₁₅ = 1 - 0.2 = 0.8

Applying Lognormal distribution : Zt = mean + ( K₂ * std ) --- ( 1 )

K₂ = 2.054 + ( 67.72 - 50 ) / ( 100 - 50 ) * ( 2.326 - 2.054 )

    = 2.1504

back to equation 1

Zt = 1.835 + ( 2.1504 * 0.65 )  = 3.23276

hence:

Log₁₀ ( Qt(ft^3/s) ) = Zt  = 3.23276

hence ; Qt = 10^3.23276

                  = 1709.07 ft^3/s

4 0
3 years ago
In what flight condition is torque effect the greatest in a single-engine airplane?
Tema [17]

Answer:

Low airspeed, high power, high angle of attack

7 0
2 years ago
On a date when the earth was 147.4x106 km from the sun, a spacecraft parked in a 200 km altitude circular earth orbit was launch
rewona [7]

Answer:

ΔV =  =v_{p} -v_{c} = 3.337 \frac{km}{s}

Explanation:

Distance of earth from sun = R_{2} = 147.4 \times 106 Km

Spacecraft perihelion = R_{2} = 120\times106Km

gravitational parameters are now given as

\mu_{sun} = 132.7\times 10^{9}

\mu_{earth} = 398600

radius of earth  = 6378 Km

Heliocentric spacecraft velocity at earth sphere of influence =

   V_{D}^{v} =\sqrt{2\mu_{sun}} \sqrt{\frac{R_{2} }{R_{1}(R_{1} +R_{2} ) } }

V_{D}^{v} =28.43\frac{km}{s}

Heliocentric velocity of earth = v_{earth} = 30.06\frac{km}{sec}

V_{infinity}= v_{earth}-V_{D}^{v} =30.06-28.43=1.57g\frac{km}{s}

assume

r_{p} =r_{earth} +r_{altitude} =6378 + 200 = 6578Km

Geometric spacecraft velocity of spacecraft at perigee of departure hyperbola

v_{p}=\sqrt{v^{2} _{infinity}+\frac{2\mu_{earth} }{r_{p} } } = 11.12\frac{km}{s}

geometric space craft velocity in its circular parking orbit

v_{c}=\sqrt{\frac{\mu_{earth} }{r_{p} } }  = 7.784 \frac{km}{s}

              ΔV =  =v_{p} -v_{c} = 3.337 \frac{km}{s}

7 0
4 years ago
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