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lesya692 [45]
4 years ago
8

The extruder head in a fused- deposition modeling setup has a diameter of 1.25 mm (0.05 in) and produces layers that are 0.25mm

(0.01 inn) thick. If the extruder head and polymer extrudate velocities are both 40mm/s, estimate the production time for the generation of a 38-mm (1.5 in., edge length) solid cube. Assume that there is a 15- second delay after deposition of each layer as the extruder head is moved over a wire brush for cleaning.
Engineering
1 answer:
Angelina_Jolie [31]4 years ago
6 0

Answer:

The time taken will be "1 hour 51 min". The further explanation is given below.

Explanation:

The given values are:

Number of required layers:

= \frac{38}{0.25}

= 152 \ layers

Diameter (d):

= 1.25 mm

Velocity (v):

= 40 mm/s

Now,

The area of one layer will be:

= 38\times 38 \ mm^2

= 1444 \ mm^2

The area covered every \second will be:

= d\times v

= 1.25\times 40

= 50 \ mm^2

The time required to deposit one layer will be:

= \frac{1444}{50}

= 28.88 \ sec

The time required for one layer will be:

= 15 \ sec

∴ Total times required for one layer will be:

= 15+28.88

= 43.88 \ sec

So,

Number of layers = 152

Therefore,

Total time will be:

= 152\times 43.88

= 6669.76 \ sec

= 1 \ hour \ 51 \ min

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