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max2010maxim [7]
2 years ago
14

How to study thermodynamics?​

Engineering
2 answers:
garik1379 [7]2 years ago
8 0
Thermodynamics is one of the few engineering courses that I would say are more conceptual than computaional. I can not emphasise how important it is to fully understand thermodynamic terminology and process. Once you understand those any problems can be easily worked out.

What I recommend is that you go through you thermodynamics book and read it carefully highlighting the important points and summarizing them in a spare notebook. The first few chapters are full of indroductory concepts such as the state of a system, processes, closed and open systems, etc. That I reccomend you memorize(with understanding ofcourse) as these are carried on all throughout.

As chapters get more complex I recommend flow charts and mind maps with as much condensed information as possible.
Hope this helps <3
Help me and mark as brainliest plz
expeople1 [14]2 years ago
7 0

It is study of the relationships between heat, temprature, work and energy

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A cylindrical tank is required to contain a gage pressure 560 kPa . The tank is to be made of A516 grade 60 steel with a maximum
adoni [48]

Answer:

5.6 mm

Explanation:

Given that:

A cylindrical tank is required to contain a:

Gage Pressure P = 560 kPa

Allowable normal stress \sigma = 150 MPa = 150000 Kpa.

The inner diameter of the tank = 3 m

In a closed cylinder  there exist both the circumferential stress and the longitudinal stress.

Circumferential stress \sigma = \dfrac{pd}{2t}

Making thickness t the subject; we have

t = \dfrac{pd}{2* \sigma}

t = \dfrac{560000*3}{2*150000000}

t = 0.0056 m

t = 5.6 mm

For longitudinal stress.

\sigma = \dfrac{pd}{4t}

t= \dfrac{pd}{4*\sigma }

t = \dfrac{560000*3}{4*150000000}

t = 0.0028  mm

t = 2.8 mm

From the above circumferential stress and longitudinal stress; the stress with the higher value will be considered ; which is circumferential stress and it's minimum value  with the maximum thickness = 5.6 mm

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3 years ago
Question 21(Multiple Choice
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ss7ja [257]

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C.) Weight and distance I believe

Explanation:

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3 years ago
Two different fuels are being considered for a 2.5 MW (net output) heat engine which can operate between the highest temperature
sveta [45]

Answer:

If the heat engine operates for one hour:

a) the fuel cost at Carnot efficiency for fuel 1 is $409.09 while fuel 2 is $421.88.

b) the fuel cost at 40% of Carnot efficiency for fuel 1 is $1022.73 while fuel 2 is $1054.68.

In both cases the total cost of using fuel 1 is minor, therefore it is recommended to use this fuel over fuel 2. The final observation is that fuel 1 is cheaper.

Explanation:

The Carnot efficiency is obtained as:

\epsilon_{car}=1-\frac{T_c}{T_H}

Where T_c is the atmospheric temperature and T_H is the maximum burn temperature.

For the case (B), the efficiency we will use is:

\epsilon_{b}=0.4\epsilon_{car}

The work done by the engine can be calculated as:

W=\epsilon Q=\epsilon H_v\cdot m_{fuel} where Hv is the heat value.

If the average net power of the engine is work over time, considering a net power of 2.5MW for 1 hour (3600s), we can calculate the mass of fuel used in each case.

m=\frac{P\cdot t}{\epsilon H_v}

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TC=m\cdot c

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