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Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Answer:
Step-by-step explanation:
There is a specific order to do these kind of problems..
first, we do everything in parenthesis...
(9 + 8) + 6/3 - 7 * 2
17 + 6/3 - 7 * 2
now, starting from the LEFT side, do all multiplication and division in the order it comes
17 + 2 - 14
now, starting from the LEFT side, do all addition and subtraction in the order it comes
19 - 14 = 4
so ur answer is 4
Learn this...order of operations....this is the order u do these problems in..
PEMDAS
P = parenthesis
E = exponents
M = multiplication
D = division
A = addition
S = subtraction
keep in mind, multiplication/division are done from left to right....u do not have to do multiplication before u do division....it just depends on which comes first when starting from the left side.....that also applies to addition/subtraction
Answer:
A) 10-20
Step-by-step explanation:
Its A because it started with 0 and it went to 10 so it adds 10 each time cause it gave us the hint with 0 to 10,
I hope this helps
