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s344n2d4d5 [400]
2 years ago
12

Johanna is studying what happens to the energy as a ball rolls down a ramp. what is she studying? select three options. gravitat

ional potential energy electrical energy kinetic energy mechanical energy elastic potential energy
Physics
1 answer:
inessss [21]2 years ago
3 0

Answer:

a c d the correct ....

Explanation:

...........

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A cylindrical block of mass M=50kg and height h=0.2m is hanging on a rope and is in equilibrium. Any difference in atmospheric p
agasfer [191]

Answer:

\Delta P = 1961.4\,Pa

Explanation:

The difference of pressure is given by gauge pressure:

\Delta P = \rho_{w}\cdot g \cdot \Delta h

\Delta P = \left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.2\,m)

\Delta P = 1961.4\,Pa

8 0
3 years ago
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Light my fire! Mix me with cerium and we’ll make beautiful mischmetal together!
Vika [28.1K]

Answer:HAHAHAHHAHHA

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3 years ago
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Please explain what is couloms law?
svp [43]

Answer:

Coulomb's law states that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the square of the separation distance between the two objects.

Explanation:

4 0
3 years ago
A man is 40 kg . calculate his weight.(g=10m/s^2)
Dafna1 [17]

{ \large{ \bf{Weight = mg}}}

{ \large{ \bf{Mass = 40 \:  kg \:  \:  \:  \: (given)}}}

{ \large{ \bf{Weight = 40 \times 10}}}

{ \large{ \therefore{ \bf{ \red{ Weight = 400N}}}}}

5 0
3 years ago
6. The hole on a level, elevated golf green is a horizontal distance of 150 m from the tee and at an elevation of 12.4 m above t
Georgia [21]

Answer:

u = 104.68 m/s

Explanation:

given,

horizontal distance = 150 m

elevation of  12.4 m

angle = 8.6°

horizontal motion = x = u cos θ. t .............(1)

vertical motion =

y = u sin \theta - \dfrac{1}{2}gt^2................(2)

from equation(1) and (2)

y = x tan \theta - \dfrac{gx^2}{2u^2cos^2\theta}..........{3}

12.4 = 150\times tan (8.6) - \dfrac{9.8\times 150^2}{2u^2cos^2(8.6)}

\dfrac{9.8\times 150^2}{2u^2cos^2(8.6)} = 10.29

\dfrac{9.8\times 150^2}{2\times 10.29\times cos^2(8.6)} = u^2

u = \sqrt{10959.34}

u = 104.68 m/s

The initial speed of the ball is u = 104.68 m/s

8 0
3 years ago
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