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Gwar [14]
3 years ago
15

An interaction of systems allows for the body to warm itself when it is cold. Which processes help the body warm up when it is c

old? Select three options. shivering sweating hair on body laying flat goosebumps forming hair on body standing up
Chemistry
2 answers:
Dmitry_Shevchenko [17]3 years ago
6 0

Answer:

shivering

hair on the body standing up

goosebump forming

Explanation:

The processes that help the body warm-up from the available options include <em>the shivering of the body</em>, <em>formation of goosebumps on the skin</em>, and <em>the standing up of hairs on the body.</em>

When the temperature of the body falls below the setpoint or the environment is cold, a homeostatic response is triggered and a signal is sent from the control center to the muscles of the body. <u>The muscles start shaking in order to generate heat to raise the temperature of the body</u>. At the same time, <u>the tiny muscles at the base of the hairs on the skin contract and pull the hairs erect, causing goosebumps in the process.</u>

zzz [600]3 years ago
3 0

Answer:

a, d, e

Explanation:

i got it right on edge.

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If a chemist has 2.3 moles of arsenic (as) that has a molar mass of 74.92 g/mol, which would be the best way to find out how man
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The best way to determine the number of atoms of arsenic in the sample will be to multiply 2.3 by Avagadro's number.
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3 0
3 years ago
A sample of gas occurs 9.0mL at a pressure of 500mmHg. A new volume of the same sample is at 750mmHg. Use two significant figure
Anit [1.1K]

Answer:

V₂ = 6.0 mL

Explanation:

Given data:

Initial volume = 9.0 mL

Initial pressure = 500 mmHg

Final volume = ?

Final pressure = 750 mmHg

Solution:

According to Boyle's Law

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

V₂ = 500 mmHg × 9.0 mL / 750 mmHg

V₂ = 4500 mmHg .mL / 750 mmHg

V₂ = 6.0 mL

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3 years ago
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C.
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How do mutations affect natural selection.
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2 years ago
How many moles of tin,Sn, are in 2500 atoms of tin?
Assoli18 [71]

Answer:

4.15×10⁻²¹ moles of Sn

Explanation:

This question can be solved by a simple rule of three.

We know that 1 mol contains 6.02×10²³ particles.

In this case, our particles are the atoms, so:

6.02×10²³ atoms / 1 mol . 2500 atoms = 4.15×10⁻²¹ moles.

The knowledge of mol can be applied for everything:

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3 years ago
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