Answer:
Radius of the interior sphere = 3.847 nm
Explanation:
The volume of the shell (Vs) is equal to the difference of the volume of the outer sphere (Vo) and the volume of the inner sphere (Vi). Then:
If we express the radius of the outer sphere (ro) in function of the radius of the inner sphere (ri), we have (e being the shell thickness):
The first equation becomes
To find ri that satisfies this equation we have to find the roots of the polynomial.
Numerically, it could be calculated that ri=3.847 nm satisfies the equation.
So if the radius of the interior sphere is 3.847 nm, the volume of the interior sphere is equal to the volume of the shell of 1nm.
Answer:
Being a reaction that releases heat, it is considered exothermic.
Explanation:
That is why if we consider it exothermic, the heat that is released to the medium is chemical energy lost from the interaction between the chemical bonds throughout the reaction. Having said this, we can affirm that the energy of the links of the products IS LESS than that of the REAGENTS, otherwise it happens in the endothermic ones, where it occurs in a vice versa.
These processes tend to have greater entropy and greater disorder in the reaction, greater kinetic energy between the particles.
Answer:
The value of is 0.02495.
Explanation:
Initial concentration of gas = 0.675 M
Initial concentration of gas = 0.973 M
Equilibrium concentration of mustard gas = 0.35 M
initially
0.675 M 0.973 M 0
At equilibrium ;
(0.675-0.35) M (0.973-2 × 0.35) M 0.35 M
The equilibrium constant is given as :
The relation between and are :
where,
= equilibrium constant at constant pressure = ?
= equilibrium concentration constant =14.45
R = gas constant = 0.0821 L⋅atm/(K⋅mol)
T = temperature = 20.0°C =20.0 +273.15 K=293.15 K
= change in the number of moles of gas = [(1) - (1 + 2)]=-2
Now put all the given values in the above relation, we get:
The value of is 0.02495.