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alina1380 [7]
2 years ago
11

Balanced Forces acting on an object will not change the object's motion. Unbalanced Forces acting on an object will change the c

hange the object's motion.
Physics
1 answer:
ale4655 [162]2 years ago
4 0

Answer:

TRUE

Explanation:

The answer is true.

Balance forces acting on a body will not change the motion of the body because the body experiences no net resultant force in one direction. When any body experiences equal forces with opposite directions, the net force or the resultant force experience by the body is zero.

In case of an unbalanced forces, there is a net force acting in one direction and so it causes the body to change in its state of motion in the direction of the net force.

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xIn the reaction A B + C + heat, ______. there is a net input of energy the potential energy of the products is greater than tha
kow [346]

Answer: Option (d) is the correct answer.

Explanation:

A chemical reaction in which heat energy is liberated is known as an exothermic reaction.

For example, A \rightarrow B + C + Heat

In an exothermic reaction, energy of reactants is more than the energy of products.

This means that potential energy of products is less than the potential energy of reactants.

Thus, we can conclude that in the reaction A \rightarrow B + C + heat, the potential energy of the products is less than that of the reactant.

6 0
2 years ago
Two in-phase loudspeakers, which emit sound in all directions, are sitting side by side. One of them is moved sideways by 4.0 mm
loris [4]

Answer:

4.4721m

Explanation:

#Use Pythagorean theorem to find the distance between the two speakers:

a^+b^2=c^2\\4^2+2^2=d^2\\\sqrt{20}\ mm=d

There are antinodes 1/4,1/2 and 3/4 of the distance between speakers.

The greatest antinode is 3/4-1/4=1/2

#Distance between consecutive antinodes is:

0.5\times \sqrt{20}=\lambda/2\\\\\lambda=4.4721m

Hence, the maximum possible wavelength of the sound waves is 4.4721m

6 0
2 years ago
The SI unit of power is the watt. Which of the following units are equivalent to the watt?
Llana [10]

Answer:

The right option is (A) V.A

Explanation:

Power: This is the rate at which work is done. Or it is the produce of force and velocity. The S.I unit of power is Watt (W). Other units include Horse power(hp), foot-pound per minutes, etc.

Generally, power can be represented as,

Power = Energy/time

P = W/t......................... Equation 1

Where p = power, w = Work or energy, t = time in seconds.

Electrical energy: This is the product of potential difference and the quantity of charge.

∴ W = VQ............................... Equation 2

Where V = potential difference, Q = quantity of charge and W = Energy or Work done.

Also Q = It........................ Equation 3.

where I = current in ampere, t = time in seconds

Substituting equation 3 into equation 3

W = VIt............................ Equation 4.

Also substituting Equation 4 into Equation 1

P = VIt/t = VI = voltage(V)×Current(A)

Therefore the equivalent unit of power is

P = V.A.

The right option is (A) V.A

3 0
3 years ago
Three different people weight a standard mass of 2.00 g on the same balance. Each person obtains a reading of 2.32 g for the mas
Lubov Fominskaja [6]

Answer: precise

Explanation:

Three different people weight a standard mass of 2.00 g on the same balance. Each person obtains a reading of 2.32 g for the mass of the standard. These results imply that the balance that was used is precise.

Precision can be defined as the closeness of measured values to each other, for a measuring equipment it is the closeness of the values of readings obtained at different times to each other. It does not necessarily means the measurements are accurate(closeness to the actual value). Therefore, in the case above where three different people measured the same mass on the same balance, and each of them obtained the same value which is different from the standard value. We can say the balance used is precise because the three readings are the same.

5 0
3 years ago
An exoplanet has three times the mass and one-fourth the radius of the Earth. Find the acceleration due to gravity on its surfac
Harlamova29_29 [7]

Answer:

b. 48.0 g.

Explanation:

Given;

mass of the exoplanet, M_p = 3M_e

radius of the exoplanet, r_p = \frac{1}{4} r_e

The acceleration due to gravity of the planet is calculated as;

g_p = \frac{GM_p}{r_p^2} \\\\for \ Earth's \ surface\\\\g = \frac{GM_e}{r_e^2} \\\\G = \frac{gr_e^2}{M_e} = \frac{g_pr_p^2}{M_p} \\\\\frac{gr_e^2}{M_e} = \frac{g_p(\frac{r_e}{4}) ^2}{3M_e} \\\\\frac{gr_e^2}{M_e} = \frac{g_pr_e ^2}{16\times 3M_e} \\\\g = \frac{g_p}{48} \\\\g_p = 48  \ g

Therefore, the correct option is b. 48.0 g

5 0
2 years ago
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