Answer:
50.67
Explanation:
L = 4 m
Let the mass of small length dx is dm.
So, dm = ρ(x) dx
Integrate on both the sides within proper limits
![m = \left [ 10x+\frac{4}{3}x^{\frac{3}{2}} \right ]_{0}^{4}](https://tex.z-dn.net/?f=m%20%3D%20%5Cleft%20%5B%2010x%2B%5Cfrac%7B4%7D%7B3%7Dx%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%20%5Cright%20%5D_%7B0%7D%5E%7B4%7D)
m = 40 + 32 / 3 = 152 / 3 = 50.67
Ok I did some research and I think the answer your looking for is the thinning of earths crust occur and i got it right on the test
Answer:
False.
Explanation:
No. Voltage does not alternate between zero and positive or negative. In non return signaling (NRZ) voltage at zero represents the 0 bit and at the positive represent the 1 bit. NRZ is one of the signal levels of uni polar Scheme in which the signal does not return to zero at the middle of it. For example 10110. That is why it named as the non return signaling.
Answer:
Explanation:
First, we need to solve for the power absorbed by the bulb.
Formula [ p = vi ]
p = 12 * 150 * 10^-3
p = +1.8W
Second, we can solve for the power aborbed in a interval of 20 minutes.
Formula [ e = vit ]
e = 12 * 150 * 10^-3 * 20 * 60
e = 2,160J
Just a note that "20 * 60" represents the time given in seconds.
Best of Luck!
