<span>The equation that describes the problem is Fe(NO3)3(aq) + 3NaOH(aq) ---> Fe(OH)3(s) + 3 NaNO3(aq)
The Net ionic equation is written as follows:
Fe^3(aq) + 3NO3-(aq) + 3Na+(aq) + 3OH-(aq) ---> Fe(OH)3(s) + 3Na+(aq) + 3NO^3-(aq)</span>
The volume of the balloon is approximately 2652 liters.
<h3>How to determine the volume occupied by the gas in a balloon </h3>
Let suppose that <em>flammable</em> hydrogen behaves ideally. GIven the molar mass (
), in kilograms per kilomole, and mass of the gas (
), in kilograms. The volume occupied by the gas (
), in cubic centimeters, is found by the equation of state for <em>ideal</em> gases:
(1)
Where:
- Ideal gas constant, in kilopascal-cubic meters per kilomole-Kelvin.
- Temperature, in Kelvin
- Pressure, in kilopascals
If we know that 
, 
, 
, 
and 
, then the volume of the balloon is:
(
)
The volume of the balloon is approximately 2652 liters. 
To learn more on ideal gases, we kindly invite to check this verified question: brainly.com/question/8711877
Absorbed photon energy
Ea = hc/λ.. (Planck's equation)
Ea = hc / 92.05^-9m
<span>Energy emitted
Ee = hc/ 1736^-9m </span>
Energy retained ..
∆E = Ea - Ee = hc(1/92.05<span>^-9 - 1/1736^-9) </span>
<span>∆E = (6.625^-34)(3.0^8) (1.028^7)
∆E = 2.04^-18 J </span>
<span>Converting J to eV (1.60^-19 J/eV)
∆E = 2.04^-18 / 1.60^-19
∆E = 12.70 eV </span>
<span>Ground state (n=1) energy for Hydrogen = - 13.60eV </span>
<span>New energy state = (-13.60 + 12.70)eV = -0.85 eV </span>
<span>Energy states for Hydrogen
En = - (13.60 / n²) </span>
n² = -13.60 / -0.85 = 16
n = 4
Protons are positively charged neutrons are neutrally charged amd electrons are negatively charged. Therefore only the protons in this instance are charged
Answer:o It is important to realise that mixing will be small unless there are electrons in the 4a1 LUMO, this is why NH3 is pyramidal while BH3 is planar! ... This mixing is very strong and stabilises the 3a1 MO substantially and hence NH3 is trigonal pyramidal and not planar.
Explanation:
