Explanation:
We know that Ionic radius increases on going downwards in any group. In group 15, the last elements Sb and Bi have ionic radii lesser than the rest of its elements i.e N,P and As.
This is due to the fact that Sb and Bi have completely filled d and f sub-shells which have least shielding effect.
Thus, they do not guard the valence electrons to a greater extent due to which the valence electrons feel almost whole nuclear charge.
This, results into attraction of valence electrons towards nucleus and hence size decreases.
Answer:
<h3>The answer is 0.79 g/mL</h3>
Explanation:
The density of a substance can be found by using the formula
From the question
mass of ethyl alcohol = 63.3 g
volume = 80 mL
The density is
We have the final answer as
<h3>0.79 g/mL</h3>
Hope this helps you
Answer:
12.4 × 10∧3 atoms
Explanation:
Given data:
moles of oxygen molecule= 1.0000 x 10-20 mol
atoms =?
Solution:
32 g O2 = 1 mol = 6.02 × 10∧23
1.0000 x 10∧-20 mol × 6.02 × 10∧23 × 2 = 12.4 × 10∧3 atoms
Answer: E
How much NH₃ can be produced from the reaction below:
N₂ + 3H₂ - 2NH₃
The stoichiometric ratio of the reactants = 1:3
Given
74.2g of N₂, and Molar mass = 14g/mole
Mole of N₂ = 74.2/14=5.3mols of N₂,
and 14mols of H₂
From this given values and comparing with the stoichiometric ratio, H₂ will be the limiting reagent while N₂ is the excess reactant.
i.e, for every 14mols of H₂, we need 4.67mols of N₂ to react with it to produce 9.33mols of NH₃ as shown (vice versa)
From this we have 9.33mols of NH₃ produced
Avogadro constant, we have n = no of particles = 6.022x10²³ molecules contained in every mole of an element.
For a 9.33mols of NH3, we have 9.33x6.022x10²³molecules in NH3
5.62x10²⁴molecules of NH₃
90 grams due to laws of conservation of mass. Input mass always = output mass. It may come out in a different form but it's always the same mass.