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IRISSAK [1]
3 years ago
14

How many moles of Na are in 11.9 grams of Na

Chemistry
2 answers:
hram777 [196]3 years ago
8 0

Answer:

sdgas

Explanation:

as dggsda

SVEN [57.7K]3 years ago
7 0
I think there are 0.5 moles of ana
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5. Which one of these species is an ion?
Maksim231197 [3]

The species that represents an ion is B³+ (option A).

<h3>What is an ion?</h3>

An ion is an atom or group of atoms bearing an electrical charge, such as the sodium and chlorine atoms in a salt solution.

Simply put, an ion is said to be an electrically charged atom. This refers to the difference in the number of protons and electrons in the atom of an element.

According to this question, the species with an electrical charge is B³+, hence, it represents an ion.

Learn more about ion at: brainly.com/question/14982375

#SPJ1

4 0
1 year ago
PlEASE HELP! 40!
podryga [215]

Answer:

moles Na = 0.1114 g / 22.9898 g/mol=0.004846

moles Tc = 0.4562g /98.9063 g/mol=0.004612

mass O = 0.8961 - ( 0.1114 + 0.4562)=03285 g

moles O = 0.3285 g/ 15.999 g/mol=0.02053

divide by the smallest

0.02053/ 0.004612 =4.45 => O

0.004846/ 0.004612 = 1.0 => Tc

to get whole numbers multiply by 2

Na2Tc2O 9

Explanation:

Hope it right hope it helps

5 0
3 years ago
PLEASEEEE HELP ASAP!!!!!!!
ankoles [38]

Answer:

15

Explanation:

3 0
4 years ago
A buffer solution contains 0.496 M hydrocyanic acid and 0.399 M sodium cyanide . If 0.0461 moles of sodium hydroxide are added t
pochemuha

Answer : The pH of the solution is, 9.63

Explanation : Given,

The dissociation constant for HCN = pK_a=9.31

First we have to calculate the moles of HCN and NaCN.

\text{Moles of HCN}=\text{Concentration of HCN}\times \text{Volume of solution}=0.496M\times 0.225L=0.1116mole

and,

\text{Moles of NaCN}=\text{Concentration of NaCN}\times \text{Volume of solution}=0.399M\times 0.225L=0.08978mole

The balanced chemical reaction is:

                          HCN+NaOH\rightarrow NaCN+H_2O

Initial moles     0.1116       0.0461     0.08978

At eqm.       (0.1116-0.0461)    0       (0.08978+0.0461)

                        0.0655                       0.1359

Now we have to calculate the pH of the solution.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

Now put all the given values in this expression, we get:

pH=9.31+\log (\frac{0.1359}{0.0655})

pH=9.63

Therefore, the pH of the solution is, 9.63

4 0
3 years ago
What two factors affect the force of friction?
Sav [38]
Roughness of the surface and weight of the object.
3 0
3 years ago
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