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3 years ago

Which statement is true about .75z = .25z -3 + 5

Mathematics

1 answer:

stepladder [879]3 years ago

4 0

<span>.75z = .25z -3 + 5
</span><span>.75z = .25z + 2
.50 z = 2
z = 4

answer
</span>a. one solution ( z = 4)

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Hich value, when placed in the box, would result in a system of equations with infinitely many solutions?

Jobisdone [24]

The value placed in the box that makes the system of equation with infinitely many solution is 12.

<h3>How to solve an infinitely many solution equation?</h3>

An infinite solution has both sides equal. For example, 6x + 2y - 8 = 12x +4y - 16. If we simplify the equation we will notice both sides are equal. This means the equation has an infinitely many solution.

Hence,

y = -2x + 4

Therefore,

6x + 3y = 12

divide the equation(ii) by 3

2x + y = 4

y = -2x + 4

Therefore, both equation are equal if the the box is filled with 12. This means for the value placed in the box that makes the system of equation with infinitely many solution is 12.

learn more on equation here: brainly.com/question/13116557

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5 0

1 year ago

(2r - 6)(-5r+4) what is the product

Akimi4 [234]

Answer:

$-10r^{2} +38r-24$

Step-by-step explanation:

Apply FOIL method: $(a+b)(c+d)=ac+ad+bc+bd$

$a=2r,b=-6,c=-5r,d=4$

$=2r(5-r)+2r*4+(-6)(-5r)+(-6)*4$

Apply minus - plus rules

$+(-a)=-a,(-a)(-b)=ab$

$=-2*5rr+2*4r+6*5r-6*4$

Simplify

Multiply $-2*5rr=-10r^{2}$

$=-10r^{2} +2*4r+6*5r-6*4$

Multiply $2*4r=8r$

$=-10r^{2} +8r+6*5r-6*4$

Multiply $6*5r=30r$

$=-10r^{2} +8r+30r-6*4$

Combine like terms

$=-10r^{2} +38r-6*4$

Multiply $-6*4=-24$

$=-10r^{2} +38r-24$

$-10r^{2} +38r-24$

6 0

2 years ago

THE PROBABILITY OF A FOOTBALL TEAM WINNING A MATCH IS 0.3 THE PROBABILTITY OF THE SAME FOOTBALL TEAM LOSING IS 0.55 WHAT IS THE

Sav [38]

Answer:

$P(Win) = 0.30$

Step-by-step explanation:

Given

$P(Win) = 0.30$

$P(Lose) = 0.55$

Required

$P(Win)$

This is already stated in the question as:

$P(Win) = 0.30$

5 0

2 years ago

Suppose given △ABD and △CBD.

patriot [66]

Answer:

The required result is proved with the help of angle bisector theorem.

Step-by-step explanation:

Given △ABD and △CBD, AE and CE are the angle bisectors. we have to prove that $\frac{AD}{AB}=\frac{DC}{CB}$

Angle bisector theorem states that an angle bisector of an angle of a Δ divides the opposite side in two segments that are proportional to the other two sides of triangle.

In ΔADB, AE is the angle bisector

∴ the ratio of the length of side DE to length BE is equal to the ratio of the line segment AD to the line segment AB.

$\frac{DE}{EB}=\frac{AD}{AB}$ → (1)