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WINSTONCH [101]
3 years ago
5

1. Place the term in the correct category according to whether it is a transfer or a reservoir in the water cycle. ( please use

all of the terms listed below.)
[Run off, Transpiration,Condensation,Groundwater flow,Stream,Cloud
Atmosphere,Ocean,]

Transfer Reservoir

2. Place the step of the water cycle into the correct category according to what force/energy causes it to happen. ( Please use all of the terms listed below.)
[Infiltration,Run Off,Precipitation,Groundwater Flow,Evaporation,Transpiration.]

Heat gravity
Chemistry
1 answer:
earnstyle [38]3 years ago
7 0

Answer:

hi :p

Explanation:

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Answer:

0.20 times 10(-5)

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Caluclate the volume of0,25 mol dm -^3 hydrochloric acid required to neutralize 2.0 dm^3 of 0,15 mol dm-^3 barium hydroxide
inessss [21]

Answer:

2.4 dm-3

Explanation:

Equation of the reaction;

2HCl(aq) + Ba(OH)2(aq) -------> BaCl2(aq) + 2 H2O(l)

Volume of acid VA = ??

Concentration of acid CA = 0.25 moldm-3

Volume of base VB = 2.0 dm^3

Concentration of base CB = 0.15 moldm-3

Number of moles of acid NA = 2

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CAVA/CBVB = NA/NB

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VA = 0.15 * 2 * 2/0.25 *1

VA = 2.4 dm-3

4 0
3 years ago
Read 2 more answers
Question:<br> What is the molar concentration of 1.29 mol of KCL dissolved in 350 mL of solution?
STatiana [176]

Answer:

M = 3.69 M.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the molar concentration of the 1.29 moles of KCl in 350 mL of solution by recalling the mathematical definition of molarity as the division of the moles by the volume in liters, in this case 0.350 L; thus, we proceed as follows:

M=\frac{1.29mol}{0.350L}\\\\M=3.69M

Which gives molar units, M, or just mol/L.

Regards!

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