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ELEN [110]
3 years ago
5

The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abb

reviation (w/v) is also common. How many grams of sucrose are needed to make 765 mL of a 31.0 % (w/v) sucrose solution?
Chemistry
1 answer:
ololo11 [35]3 years ago
4 0

Answer:

There are needed 237.15 g of sucrose.

Explanation:

The 31.0 % (w/v) of the sucrose solution means that in 100 ml of solution, you have 31 g of solute, in this case sucrose.

So you want to make a solution with 765 mL.

Let's think the rule of three:

100 mL solution__contain __31 g sucrose

765 mL solution _________ (765 . 31 ) /100 = 237.15 g

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PLEASE HELP !!!
garri49 [273]
According to the Law of Definite Proportions from Dalton's Atomic Theory, each compound is composed of a fixed ratio of each of its individual elements. So, the number of individual elements per 1 particle of that compound is represented by the subscripts. The answers are as follows:

Table sugar: 12 atoms of carbon, 22 atoms of hydrogen; 11 atoms of oxygen; 45 total atoms
Marble: 1 atom of calcium, 1 atom of carbon; 3 atoms of oxygen; 5 total atoms
Natural gas: 1 atom of carbon, 4 atoms of hydrogen; 5 total atoms
Rubbing alcohol: 3 atoms of carbon, 8 atoms of hydrogen; 1 atom of oxygen; 12 total atoms
Table sugar: 1 atom of silicon; 2 atoms of oxygen; 3 total atoms
7 0
3 years ago
The ratio of nitrogen to oxygen by mass in NO is 7.0:8.0. Identify the ratio of nitrogen to oxygen by mass in NO2 and N2O7 .
Rus_ich [418]

This problem is providing the ratio of nitrogen to oxygen by mass in nitrogen monoxide, NO, as 7.0:8.0 and asks for the same ratio but in NO₂ and N₂O₇. After doing the calculations, the results are 7.0:16.0 and 1.0:4.0 respectively.

<h3>Mass ratios:</h3>

In chemistry, one can calculate the mass ratios in chemical formulas according to the atomic mass of each atom. In such a way, one knows the mass ratio of nitrogen to oxygen in NO is 7.0:8.0 because we divide the atomic mass of nitrogen by oxygens:

\frac{14}{16}=\frac{7.0}{8.0}

Now, for chemical formulas with subscripts, one must multiply the atomic mass of the element by the subscript in the formula, which is the case of NO₂ and N₂O₇ as shown below:

NO_2:\frac{14}{16*2}=\frac{14}{32} =\frac{7.0}{16.0}  \\&#10;\\&#10;N_2O_7:\frac{14*2}{16*7}=\frac{28}{112} =\frac{1.0}{4.0}

Therefore, the results for NO₂ and N₂O₇ are 7.0:16.0 and 1.0:4.0 respectively

Learn more about atomic masses: brainly.com/question/5566317

3 0
2 years ago
Carbon has an atomic number of 6. This means it has 6 protons and 6 electrons. How many valence electrons does carbon have?
Varvara68 [4.7K]

Answer:

4

Explanation:

Carbon configuration- 2,4

Valence electrons means the outershell electrons

That means valence electrons=4

8 0
3 years ago
What is the hybridization of the central atom in becl2?
Anuta_ua [19.1K]
Its hybridization would be sp because Be only has 2 covalent bonds with Cl
4 0
2 years ago
A rubber balloon was filled with helium at 25.0˚C and placed in a beaker of liquid nitrogen at -196.0˚C. The volume of the cold
Ksenya-84 [330]

Answer:

The volume of helium at 25.0 °C is 60.3 cm³.

Explanation:

In order to work with ideal gases we need to consider absolute temperatures (Kelvin). To convert Celsius to Kelvin we use the following expression:

K = °C + 273.15

The initial and final temperatures are:

T₁ = 25.0 + 273.15 = 298.2 K

T₂ = -196.0 + 273.15 = 77.2 K

The volume at 77.2 K is V₂ = 15.6 cm³. To calculate V₁ in isobaric conditions we can use Charle's Law.

\frac{V_{1}}{T_{1}} =\frac{V_{2}}{T_{2}} \\V_{1}=\frac{V_{2}}{T_{2}} \times T_{1}=\frac{15.6cm^{3} }{77.2K} \times 298.2K=60.3cm^{3}

3 0
3 years ago
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