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ELEN [110]
3 years ago
5

The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abb

reviation (w/v) is also common. How many grams of sucrose are needed to make 765 mL of a 31.0 % (w/v) sucrose solution?
Chemistry
1 answer:
ololo11 [35]3 years ago
4 0

Answer:

There are needed 237.15 g of sucrose.

Explanation:

The 31.0 % (w/v) of the sucrose solution means that in 100 ml of solution, you have 31 g of solute, in this case sucrose.

So you want to make a solution with 765 mL.

Let's think the rule of three:

100 mL solution__contain __31 g sucrose

765 mL solution _________ (765 . 31 ) /100 = 237.15 g

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Harvey kept a balloon with a volume of 348 milliliters at 25.0˚C inside a freezer for a night. When he took it out, its new volu
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Initial volume of the balloon = V_{1}= 348 mL

Initial temperature of the balloon T_{1} = 25.0^{0}C + 273 = 298 K

Final volume of the balloon V_{2} = 322 mL

Final temperature of the balloon = T_{2} = ?

According to Charles law, volume of an ideal gas is directly proportional to the temperature at constant pressure.

\frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }

On plugging in the values,

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