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2 years ago

What is a unit vector?

Physics

1 answer:

jekas [21]2 years ago

8 0

Answer:

A unit vector is (D) a vector with a magnitude of one

Explanation:

Unit Vector Information:

A unit vector is a vector with a magnitude of one. Vectors of different magnitudes can be scaled off the unit vector. Also, they can be used in two, three, or more dimensions.

Other Answers:

A. a vector with all three directions or dimensions that are given

This is the definition of a 3D vector. This is a line segment in three-dimensional space running from point A (tail) to point B (head). Each vector has a magnitude (or length) and direction.

B. a vector with only one dimension

This is the definition of an one-dimensional vector. This type of vector has no dimension, but a number of components, therefore it behaves like a real number.

C. a vector that has an x and y components that are equal in magnitude

(Unsure, I believe this would be defined as an equal vector. Correct me if I'm wrong and I will edit it.)

I hope this helps!

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Harman [31]

there is no horizontal displacement if he went straight up

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galina1969 [7]

Answer:

The girl has greater tangential acceleration

Explanation:

The angular acceleration ( $\alpha$ ) of the merry go round is equal to the rate of the change of the angular velocity, $\omega$ :

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Since all the points of the merry go round complete 1 circle in the same time, the angular velocity of each point of the merry go round is the same, and so all the points also have the same angular acceleration.

The tangential acceleration instead is given by

$a_t = \alpha r$

where

$\alpha$ is the angular acceleration

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Since the girl is near the outer edge and the boy is closer to the centre, the value of r for the girl is larger than for the boy, so the girl has greater tangential acceleration.

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3 years ago

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3 years ago

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The barometric pressure at sea level is 30 in of mercury when that on a mountain top is 29 in. If the specific weight of air is

stealth61 [152]

To solve this problem we will apply the concepts related to pressure, depending on the product between the density of the fluid, the gravity and the depth / height at which it is located.

For mercury, density, gravity and height are defined as

$\rho_m = 846lb/ft^3$

$g = 32.17405ft/s^2$

$h_1 = 1in = \frac{1}{12} ft$

For the air the defined properties would be

$\rho_a = 0.0075lb/ft^3$

$g = 32.17405ft/s^2$

$h_2 = ?$

We have for equilibrium that

$\text{Pressure change in Air}=\text{Pressure change in Mercury}$

$\rho_m g h_1 = \rho_a g h_2$

Replacing,

$(846)(32.17405)(\frac{1}{12}) = (0.0075)(32.17405)(h_2)$

Rearranging to find $h_2$

$h_2 = \frac{(846)(32.17405)(\frac{1}{12}) }{(0.0075)(32.17405)}$

$h = 9400ft$

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3 years ago

A 1-kg iron frying pan is placed on a stove. The pan increases from 20°C to 250°

timurjin [86]

Answer;

The temperature change for the second pan will be lower compared to the temperature change of the first pan

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-Maintaining the same quantity of heat, with another pan of the same mass and greater specific heat capacity would mean that the change in temperature would be much less lower.

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