Ask question

Ask question

All categories

3 years ago

12

(a) Two point charges totaling 8.00 μC exert a repulsive force of 0.150 N on one another when separated by 0.500 m. What is the

charge on each? (b) What is the charge on each if the force is attractive?

2 answers:

Mrrafil [7]3 years ago

8 0

Answer:

3x10-7C

Explanation: Use Coulombs Law. Find q2 and derive the equation. Make sure to convert micro to decimals for accurate results

Anastaziya [24]3 years ago

7 0

3 is jxhuneuxndnzixbf

You might be interested in

A 5.0 kg wooden block is placed at an adjustable inclined plane. what is the angle of incline above which the block will start t

Aleks [24]

The value of the angle of the incline $\theta$ at which the block starts to slide is the angle at which the component of the weight parallel to the incline becomes equal to the frictional force that keeps the block on the incline:
$mg \sin \theta = \mu N$
where the term on the left is the component of the weight parallel to the incline, and the term on the right is the frictional force, which is the product between the coefficient of friction $\mu$ and the normal reaction of the incline N.

The normal reaction of the incline, N, is equal to the component of the weight perpendicular to the incline:
$N=mg \cos \theta$
Therefore, the initial equation becomes
$mg \sin \theta = \mu mg \cos \theta$
From which we find
$\tan \theta = \mu$
$\theta = \arctan \mu$

For angles above this value, the block will start sliding down, otherwise the block will stay on the incline.

3 0

3 years ago

Can someone explain the law of conservation of energy?

julsineya [31]

The law of conservation of energy is a law that states that "energy cannot be created or destroyed, only changed" this means that you can't create it or destroyed as in, if you burn wood, you have released the energy. you haven't destroyed it, you have just released it

5 0

3 years ago

An object is 45.0 kg here on Earth. What is its mass on Jupiter if the acceleration

puteri [66]

Answer:

B. 45.0 kg

Explanation:

On earth the object has ;

Mass = 45 kg

acceleration = 9.81 m/s²

On Jupiter, acceleration is 24.79 m/s²

The mass of this object on Jupiter will be 45 kg. It will not change. Mass of an object will only change when you remove part of the object from it or add to it another part. The mass is the same on Earth and on Jupiter. However, due to increased acceleration on Jupiter , the weight will change/ increase because;

Weight = mass * acceleration

<u>On Earth </u>

Weight of the object will be : 45 * 9.81 = 441.45 kg

<u>On Jupiter</u>

Weight of the object will be : 45*24.79 =1115.55 kg

8 0

3 years ago

A toy car of mass 8 kg initially moves with a speed of 5 m/s. How much work must be done on the car to increase its speed to 10

sukhopar [10]

ANSWER:

300 J

STEP-BY-STEP EXPLANATION:

To know the work required, we must calculate the work in both cases, the difference would be the amount of work necessary for the speed to increase. The work done is the same as the amount of energy increase. The formula for kinetic energy is:

$\frac{1}{2}m\cdot v^2$

We calculate in each case:

$\begin{gathered} \frac{1}{2}\cdot8\cdot10^2=400\text{ J} \\ \frac{1}{2}\cdot8\cdot5^2=100\text{ J} \end{gathered}$

We calculate the difference between the two to find out the work required:

$400-100=300\text{ J}$

The work required is 300 J

3 0

2 years ago

Suppose you start an antique car by exerting a force of 270 N on its crank for 0.275 s. What angular momentum is given to the en

Ksenya-84 [330]

Answer:

$L_f=22.27\ kg-m^2/s$

Explanation:

Given that,

Force exerted on an antique car, F = 270 N

Time, t = 0.275 s

Distance, d = 0.3 m

To find:

The angular momentum given to the engine.

Solution,

We know that the relation between the angular momentum and the torque is given by :

$\tau=\dfrac{dL}{dt}$

Since, $\tau=d\times F$

$dF=\dfrac{dL}{dt}$

$d.F=\dfrac{L_f-L_i}{t}$

$d.F=\dfrac{L_f}{t}$

$L_f=d\times F\times t$

$L_f=0.3\ m\times 270\ N\times 0.275\ s$

$L_f=22.27\ kg-m^2/s$

So, the angular momentum given to the engine is $22.27\ kg-m^2/s$ .

7 0

4 years ago