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3 years ago

Calculate 4 Srxn for this equation. Round to the

Chemistry

1 answer:

masya89 [10]3 years ago

7 0

Answer:

On edge nuity, it is 79.

Explanation:

Please read the explanation.

Since u have no coefficients, this problem is super easy.

You just add your products, 115.5+69.91 = 185.41

Then add your reactants: 49.8+56.5= 106.3

Then subtract your reactants from your product and round to the nearest whole number.

106.3-185.41=79

It's really easy. Once u understand it, you can do any problem like this. If there is coefficients, just multiply the coefficient by the amount given to you in the problem.

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How many grams of NaOH would be required to make 1.0 L of a 1.5 M solution

omeli [17]

60 grams are required.

Hope this helped you!

4 0

3 years ago

PLEASE HELP!’ DUE IN 10 MINS

Aleksandr [31]

Answer:

The products are SnPO4 and LiC2H3O2

Explanation:

The reactants are LiPO4 + Sn(C2H3O2)2

This is a double replacement reaction

So what you do is switch the elements the other way around.

To do that, all you have to do switch Sn with PO4 since Sn is a cation and PO4 is an anion.

Then you switch Li with C2H3O2 because Li is a cation and C2H3O2 is an anion.

After that, check the charges. PO4 has -3 charge

So just leave Sn the way it is without a subscript.

In word form, the product would be Tin(III) Phosphate

C2H3O2 has a -1 charge Li has a +1 charge

So leave both of them the way it is without any subscripts.

In word form, the product would be Lithium Acetate

7 0

3 years ago

Pb(OH)Cl, one of the lead compounds used in ancient Egyptian cosmetics, was prepared from PbO according to the following recipe:

sladkih [1.3K]

Answer:

8.59 g

2.25 g

Explanation:

According to the given situation the calculation of grams of PbO and grams of NaCL is shown below:-

Moles of Pb(OH)CL is

$= \frac{Mass}{Molar\ mass}$

$= \frac{10.0 g}{259.65g / mol}$

= 0.0385 mol

Mass of PbO needed is

$= 0.385mol Pb(OH) Cl\times \frac{1 mol PbO}{1molpb (OH) cl} \times \frac{223.2g PbO}{1mol PbO}$

After solving the above equation we will get

= 8.59 g

Mass of NaCL needed is

$= \frac{1mol\ NaCl}{1molPb\ (OH)Cl} \times \frac{58.45NaCl}{1mol NaCl}$

After solving the above equation we will get

= 2.25 g

Therefore we have applied the above formula.

7 0

3 years ago

O2 would not be considered as a compound. True False

MissTica

True, a compound consists of two different molecules/atoms

4 0

4 years ago

If 8.0 g of sulfur dioxide came in contact with a cloud containing 2.2 g of oxygen, indicate the

Inga [223]

Answer:

Limiting reactant= SO₂, Theoretical yield = 9.6g SO₃

Explanation:

The first step is is to find the limiting reactant; you do this using stoichiometry.

The reactant that produces the smallest amount of sulfur trioxide SO₃, is the limiting reactant.

In this problem, SO₂ is the limiting reactant.

Now to find the theoretical yield we will use the smallest value of SO₃.

I have uploaded a picture to better illustrate the problem and hope it helps.

5 0

3 years ago