If you were given two transparent liquids how would you determine which is pure and which is salt water

Why is it important to balance the redox equation for the electrolysis of water?.

77julia77 [94]

Electrolysis is a process, which allows us to break down a chemical compound into its elements, completing the balance by adjusting the number of atoms on both sides of the reaction is important because the number of electrons given up during oxidation must be the same as the number of electrons gained during the reduction.

<h3>What is electrolysis of water?</h3>

It is a process of oxidation and reduction of one or more elements that, through the induction of electric current, breaks down the water molecule (H2O), thus producing gaseous hydrogen and oxygen.

Oxidation and reduction processes occur simultaneously and never in isolation, which is why they are called redox reactions.

Therefore, we can conclude that electrolysis is a process where electrical energy will change to chemical energy where it is important that the number of electrons given up during oxidation is the same as the number of electrons gained during reduction.

Learn more about balance of redox equations : brainly.com/question/1232351

7 0

2 years ago

A solution of fructose, C6H12O6, a sugar found in many fruits, is made by dissolving 34.0 g of fructose in 1.00 kg of water. Wha

Mashcka [7]

Answer:

Molality → 0.188 m

Mole fraction of fructose → 0.00337

Mass percent of fructose in solution → 3.29 %

Molarity → 0.183 M

Explanation:

Solute → 34 g of fructose

Solvent → 1000 g of water

Solution → 1000 g of water + 34 g of fructose = 1034 g of solution.

We take account density to calculate, the solution's density

1.0078 g/mL = 1034 g / mL

1034 g / 1.0078 g/mL = 1026 mL

Molal concentration → moles of solute in 1kg of solvent

Moles of fructose = mass of fructose / molar mass

34 g/ 180g/mol = 0.188 mol

0.188 mol/1kg = 0.188 m

Mole fraction of fructose = Moles of fructose / Total moles

We determine the moles of water

Moles of water = 1000 g / 18 g = 55.5 mol

Total moles = moles of fructose + moles of water

0.188 mol + 55.5 mol = 55.743 mol

0.188 mol / 55.743 mol = 0.00337

Mass percent = mass of fructose in 100 g of solution

(Mass of fructose / Total mass ) . 100 = (34 g /1034 g) . 100 = 3.29 %

Molarity = Moles of solute in 1L of solution

We can also say mmol of solute in 1 mL of solution

0.188 mol of fructose = 188 mmol of fructose

Molarity = 188 mmol / 1026 mL of solution = 0.183 M

8 0

3 years ago

What type of calorimeter would be best to use if you wanted to measure the heat that is released when gasoline is burned?

andrey2020 [161]

Answer:

Constant Volume Calorimeter

Explanation:

In order to measure the heat released in burning of a gasoline, we generally use closed calorimeter. It is a constant volume calorimeter.

Most common example of such calorimeter is Bomb calorimeter.

We use closed calorimeter or constant volume calorimeter as large amount of heat is released during combustion of a fuel or gasoline.

5 0

4 years ago

Read 2 more answers

Water is boiling in a clear pot, as shown in the picture. A clear pot full of water sits over gas burner. The water has large bu

Schach [20]

Transfer and gain of kinetic energy by the water molecules takes place as water cycles from the bottom of the pot toward the top.

<h3>What is thermal energy?</h3>

Thermal energy is a another word to express the heat energy.

When we boil a water over a gas burner then due to convention, heat energy can be transfer to the bottom water molecules in the form of thermal energy. After gaining the thermal energy movement of water molecules increases as a result of the increase of the kinetic energy.

Hence, option (1), (2) & (4) are correct i.e. transfer and gain of kinetic energy by the water molecules is done.

To know more about thermal energy, visit the below link:

brainly.com/question/19666326

8 0

2 years ago

A photon of green light strikes an unknown metal and an electron is emitted. The voltage is set to 2 volts. The electron cannot

SVETLANKA909090 [29]

Answer:

The correct answer is:

An electron will be emitted in the second experiment, but it cannot be determined whether it will reach the second plate.

Explanation:

In fact, violet has higher frequency than green light. This means that photons on violet carry more energy than photons of green light (remember that the energy of a photon is proportional to it's frequency:

$e = hf$

, so when they hit the surface of the metal, more energy is transferred to the electrons. The electron was already emitted with green light, so it must be emitted with also violet light, given the more energy transferred.

7 0

3 years ago