Answer:
3.97
Explanation:
pH of buffer solution = pKa+Log(Cb/Ca)
pH of buffer solution = -log(Ka)+log(Cb/Ca)............... Equation 1
Where Ca = concentration of acid, Cb = concentration of base.
Given: Ka = 6.5×10⁻⁵, Ca = 0.25 M, Cb = 0.15 M
Substitute into equation 1
pH of buffer solution = -log(6.5×10⁻⁵)+log(0.15/0.25)
pH of buffer solution = 4.19+(0.22)
pH of buffer solution = 3.97.
Answer:
See explanation
Explanation:
Barium sulphate is easily prepared by means of a double replacement reaction. A double replacement reaction is one in which the ions in each of the reactants exchange partners in the products.
For instance, we can decide to prepare barium sulphate by a double replacement reaction between sodium sulphate and barium chloride. The both starting materials are soluble compounds. However, the barium sulphate formed is an insoluble white precipitate. The precipitate is recovered by filtration, washed and dried.
The reaction equation is shown below;
Na2SO4(aq) + BaCl2(aq) -------> BaSO4(s) + 2NaCl(aq)