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3 years ago

19. Contrast mitochondria and chloroplasts. (4 points)

Chemistry

1 answer:

anyanavicka [17]3 years ago

3 0

Answer:

mitochondria are present in the cells of all types of aerobic organisms like plants and animals, whereas Chloroplast is present in green plants and some algae, protists like Euglena. Mitochondria is the colourless, bean shape organelles. Chloroplasts are green colour and disc shape organelles.

Explanation:

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Of the groups below, which are the least chemically reactive?

seropon [69]

It is actually Group 3A elements. I just took the test.

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3 years ago

By which process is sediment laid down?<br> its a test it's due at 10!

Alexus [3.1K]

Answer: Deposition

Explanation:

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Name seven characteristics that can be used to define a mineral

PIT_PIT [208]

Solid
, Inorganic,
Naturally Orcurring,
Defintite
Chemical Compostion,
Definite Crystalline Structure

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Hardness,
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3 years ago

A compound in a copper ore has the following percentage composition by mass:

AveGali [126]

1) since we are given percentages, we can assume we have 100 grams of the molecule.

55.6 % Cu ----> 55.6 grams Cu
16.4 % Fe------> 16.4 grams Fe
28.0% S--------> 28.0 grams S

2) convert each gram to moles using the molar masses given

$55.6 g Cu \frac{1 mol}{63.5 g} = 0.876 mol Cu$
$16.4 g Fe \frac{1 mol}{56.0 g} = 0.293 mol Fe$
$28.0 gS \frac{1 mol}{32.0} = 0.875 mol S$

3) we divide the smallest value of moles (0.293) to each one.

Cu --> 0.876 / 0.293= 3
Fe---> 0.293 / 0.293= 1
S-----> 0.875 / 0.293= 3

4) let's write the empirical formula

Cu₃FeS₃

6 0

3 years ago

How much water can be raised from 25*C (room temperature) to 37*C (body temperature) by adding the 2,000 kJ in a Snickers bar?

yuradex [85]

Answer:

m = 39834.3 g

Explanation:

Given data:

Mass of water raised = ?

Initial temperature = 25°C

Final temperature = 37°C

Energy added = 2000 Kj (2000 ×1000= 2000,000 j

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 37°C - 25°C

ΔT = 12°C

c = 4.184 g/j.°C

Q = m.c. ΔT

2000,000j = m .4.184 g/j.°C. 12°C

2000,000j = m. 50.208 g/j

m = 2000,000j / 50.208 g/j

m = 39834.3 g

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3 years ago