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Viktor [21]
3 years ago
11

How does skin protect the body from pathogens?

Chemistry
2 answers:
STatiana [176]3 years ago
6 0

Answer:

It blocks pathogens from getting inside our body.

Explanation:

The skin is the biggest organ, it cover the whole body and organ system from any toxic things.

andreev551 [17]3 years ago
5 0
Skin is a barrier that serves as one of the body's first lines of defense against harmful microbes. Specialized immune cells within skin tissue help to fight invading organisms. Yet the skin hosts diverse communities of beneficial bacteria, collectively known as the skin microbiota.
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What two sublevels of orbitals contain valence electrons? (s, p, d, or f)?
LuckyWell [14K]
The two sublevels are s and p. These are the main group sublevels
5 0
3 years ago
What is meant by saying that the latent heat of vaporization of water is 22. 5×10^5 j/kg.
andrey2020 [161]

It means that 22.5×10^5 J of heat is required to change 1 kg of water into steam.

Latent heat of vaporization is amount of energy required to change 1 gram (in this example 1 kilogram) of material from the liquid to the gaseous state at its boiling point.

Boiling point of the water is 100°C.

Joule (J) is the standard unit for energy (in this example heat).

Evaporization is phase change process in which the water changes from a liquid to a gas (water vapor). Fore example, solar radiation can be the source of energy for evaporation.

More about heat of vaporization: brainly.com/question/14679329

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5 0
2 years ago
State and explain the relative change in the pH and in the buffer-component concentration ratio, [NaA]/[HA], for each of the fol
BabaBlast [244]

A- and H3O+ interact, causing A-'s concentration to drop and [HA] to rise. As a result, the [NaA]/[HA] ratio declines. Because of the base content, the buffer's pH will be more acidic. The concentration of the acid, HA, has increased while A- has decreased.

What is Acid?

Any material that when dissolved in water has an acidic taste, can alter the colour of some indicators (such as reddening blue litmus paper), can react with some metals (such as iron) to release hydrogen, can combine with bases to produce salts, and can accelerate some chemical reactions (acid catalysis). Acids are examples of organic chemicals that belong to the carboxylic acid, sulfonic acid, and phenol groups as well as the inorganic substances known as the mineral acids, such as sulfuric, nitric, hydrochloric, and phosphoric acids. These chemicals contain one or more hydrogen atoms, which are discharged as positively charged hydrogen ions when they are in solution.

To learn more about Acid, visit:

brainly.com/question/14072179

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3 0
2 years ago
Balloon X is filled with the carbon monoxide. Balloon Y is filled to the same volume with carbon dioxide. The balloons are left
weqwewe [10]

Answer:

The smallest ballon is the ballon X

Explanation:

It is possible to answer this question by using Graham's law:

\frac{v_1}{v_2} =\sqrt{\frac{MW_2}{MW_1}}

Where v is the speed of effusion and MW is molar weight of each compound.

This equation is showing that speed is inversely related to the square root of its molar mass. As carbon dioxide has a bigger MW than carbon monoxide, the speed of effusion of carbon dioxide is lower doing its ballon biggest than carbon monoxide ballon, thus: <em>The smallest ballon is the ballon X</em>

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I hope it helps!

6 0
3 years ago
A quantity of 0.0250 mol of a gas initially at 0.050 L and 19.0°C undergoes a constant-temperature expansion against a constant
KiRa [710]

Answer:

V_2=2.995L\\\\W=248.5J

Explanation:

Hello,

In this case, for us to compute the final volume we apply the Boyle's law that analyzes the pressure-volume temperature as an inversely proportional relationship:

P_1V_1=P_2V_2

So we solve for V_2 by firstly computing the initial pressure:

P_1=\frac{nRT}{V_1}=\frac{0.025mol*0.082\frac{atm*L}{mol*K}*(19+273.15)K}{0.050L}  =11.98atm

V_2=\frac{P_1V_1}{P_2}=\frac{11.98atm*0.050L}{0.200atm}\\ \\V_2=2.995L

Finally, we can compute the work by using the following formula:

W=nRTln(\frac{V_2}{V_1} )=0.025mol*8.314\frac{J}{mol*K}*(19.0+273.15)K*ln(\frac{2.995L}{0.050L}) \\\\W=248.5J

Best regards.

4 0
4 years ago
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