Answer:
4.4 cm
Explanation:
Given:
Distance of the screen from the slit, D = 1 m
Distance between two third order interference minimas, x = 22 cm
Let's say, minima occurs at:
We have:
Calculating further for the width of the central bright fringe, we have:
= 4.4 cm
Note: w in representswavelength
Given:
Work done, W = 5 J
Initial energy = 8J
Final energy = 30J
Let's determine if the work done have a positive or nrgative value.
Appy the equation for the first lae of thermodynamics:
Where:
U is the change in internal energy
Q is the added heat
W is the work done
To find the work done here, we have:
Rewrite the formula for W
Where:
ΔU = 30J - 8J = 22J
Q = 5J
Thus, we have:
Therefore, the work done here is -17J.
This means the work done in this scenario has a negative value.
ANSWER:
The work done in this scenario has a negative value