Dangerous of overloading in a circuit,
1 answer:
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Answer:
the value of horizontal force P is 170.625 N
the value of horizontal force at P = 227.5 N is that the block moves to right and this motion is due to sliding.
Explanation:
The first diagram attached below shows the free body diagram of the tool chest when it is sliding.
Let start out by calculating the friction force
where :
friction force
= coefficient of friction
= normal friction
Given that:
= 0.3
0.3
Using the equation of equilibrium along horizontal direction.
P - 0
P = 0.3 ----- Equation (1)
To determine the moment about point B ; we have the expression
0 =
where;
P = horizontal force
= normal force at support A
W = self- weight of tool chest
Replacing W = 650 N
0 =
Replacing for P in equation (1)
Plugging the value of in equation (2)
P =170.625 N
Thus; the value of horizontal force P is 170.625 N
b) From the second diagram attached the free body diagram; the free body diagram of the tool chest when it is tipping about point A is also shown below:
Taking the moments about point A:
-(P × 100)+ (W×35) = 0
P =
Replacing 650 N for W
P = 227.5 N
Thus; the value of horizontal force P, when the tool chest tipping about point A is 227.5 N
We conclude that the motion will be impending for the lowest value when P = 170.625 N and when P= 227.5 N
However; the value of horizontal force at P = 227.5 N is that the block moves to right and this motion is due to sliding.
Answer:
Solution 2:
The thermal energy of any particle is given as =
where m= Effective mass of the particle,
v= Velocity of the particle
The average kinetic energy is given as =
where K= Boltzmann Constant
T= Temperautre of the particle
At equilibrium,
1/2 mv² = 3/2 KT
Hence, v=
As, effective mass ratio is calculated with respect to rest mass of electron,
melectron = 0.11 * 9.11 *10-31 kg
mhole = 0.35 *9.11 *10-31 kg
K = 1.38 × 10-23 m2 kg s-2 K-1
Plotting, over a range of temperature of 0 K to 400 K, we obtain the attached Graphs (attached).
Solution 3:
The above two curves plotted are not identical as seen. From the same value of Temperature, and under identical conditons, the Thermal velocity solely depends on effective mass ratio. And it is inversely proportional to effective mass ratio. More the effective mass ratio, less the thermal velocity and flatter the slope of the curve and vice versa. As, the mass ratio of holes is more than that of electrons, the curve of electrons has a steeper slope than that of holes. Hence, the curves are not just identical.
