Answer:
The speed of shaft is 1891.62 RPM.
Explanation:
given that
Amplitude A= 0.15 mm
Acceleration = 0.6 g
So
we can say that acceleration= 0.6 x 9.81

We know that

So now by putting the values



We know that
ω= 2πN/60
198.0=2πN/60
N=1891.62 RPM
So the speed of shaft is 1891.62 RPM.
Answer:
no need for that
Explanation:
they are not the same at all
Answer:
4.5kg/min
Explanation:
Given parameters

if we take
The mass flow rate of the second stream = 
The mass flow rate of mixed exit stream = 
Now from mass conservation


The temperature of the mixed exit stream given as

Therefore the mass flow rate of second stream will be 4.5 kg/min.