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3 years ago

Which type of energy refers to the sum of potential and kinetic energies in the particles of a substance?

Chemistry

2 answers:

baherus [9]3 years ago

6 0

Answer:

Explanation:

i did the test

MrRa [10]3 years ago

3 0

Explanation:

the sum of PE and KE is mechanical energy this means energy during motion and position I think the answer is motion and stored or it may be internal

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A hydrocarbon is a compound that contains mostly carbon and hydrogen. Calculate the percent composition (by mass) of the followi

Katena32 [7]

C7H16, where C=12.01, and H=1.01, so the weight of the molecule would be 7(12.01)+16(1.01), or 100.23. The percentage of carbon would be found by ((7*12.01)/100.23)*100=83.88% Carbon
((16*1.01)/100.23)*100=16.12% Hydrogen

7 0

3 years ago

Work is equal to the what used and multiplyed by the what over which the force was applied

Allushta [10]

W=Fd
Work is equal to the force multiplied by the distance travelled.

4 0

3 years ago

How many valence electrons are in each atom? a. potassium C. magnesium b. carbon d. oxygen

skad [1K]

Just look it up you’ll get the answers faster

7 0

2 years ago

15A.4(a) What is the temperature of a two-level system of energy separation equivalent to 400 cm−1 when the population of the up

maksim [4K]

Answer:

T = 525K

Explanation:

The temperature of the two-level system can be calculated using the equation of Boltzmann distribution:

$\frac{N_{i}}{N} = e^{-\Delta E/kT}$ (1)

where Ni: is the number of particles in the state i, N: is the total number of particles, ΔE: is the energy separation between the two levels, k: is the Boltzmann constant, and T: is the temperature of the system

The energy between the two levels (ΔE) is:

$\Delta E = hck$

where h: is the Planck constant, c: is the speed of light and k: is the wavenumber

$\Delta E = 6.63\cdot 10^{-34} J.s \cdot 3\cdot 10^{8}m/s \cdot 4 \cdot 10^{4}m^{-1} = 7.96 \cdot 10^{-21}J$

Solving the equation (1) for T:

$T = \frac{-\Delta E}{k \cdot Ln(N_{i}/N)}$

With Ni = N/3 and k = 1.38x10⁻²³ J/K, the temperature of the two-level system is:

$T = \frac{-7.96 \cdot 10^{-21}J}{1.38 \cdot 10^{-23} J/K \cdot Ln(N/3N)} = 525K$

I hope it helps you!

3 0

3 years ago

The molarity of a solution that contains 0.50 moles of naoh in 200.0 milliliters of water is

NARA [144]

200.0 mL =0.2000 L
Molarity = number of mole solute / volume solution(L) = 0.50 mol/0.2000 L=
= 2.5 mol/L =2.5M

Answer : 2.5 M

5 0

2 years ago

Read 2 more answers