Answer:
The magnitude of the electric field is ![5.1 \times 10^{11} \frac{N}{C}](https://tex.z-dn.net/?f=5.1%20%5Ctimes%2010%5E%7B11%7D%20%20%5Cfrac%7BN%7D%7BC%7D)
Explanation:
Given:
Charge of electron
C
Separation between two charges
m
For finding the magnitude of the electric field,
![E= \frac{kq}{r^{2} }](https://tex.z-dn.net/?f=E%3D%20%5Cfrac%7Bkq%7D%7Br%5E%7B2%7D%20%7D)
Where ![k = 9 \times 10^{9}](https://tex.z-dn.net/?f=k%20%3D%209%20%5Ctimes%2010%5E%7B9%7D)
![E = \frac{9 \times 10^{9} \times 1.6 \times 10^{-19} }{(5.3 \times 10^{-11} )^{2} }](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B9%20%5Ctimes%2010%5E%7B9%7D%20%5Ctimes%201.6%20%5Ctimes%2010%5E%7B-19%7D%20%7D%7B%285.3%20%5Ctimes%2010%5E%7B-11%7D%20%29%5E%7B2%7D%20%7D)
![\frac{N}{C}](https://tex.z-dn.net/?f=%5Cfrac%7BN%7D%7BC%7D)
Therefore, the magnitude of the electric field is ![5.1 \times 10^{11} \frac{N}{C}](https://tex.z-dn.net/?f=5.1%20%5Ctimes%2010%5E%7B11%7D%20%20%5Cfrac%7BN%7D%7BC%7D)
They don't have relatively the same size. The most massive atoms,
like Uranium, are much SMALLER than the least massive ones, like
Hydrogen !
That's because the most massive atoms have so many more protons ...
positively charged ... in their nucleii, pulling so much harder on the cloud
of electrons ... negatively charged.