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2 years ago

One gallon of paint covers an area of 25 m2. What is the thickness of the paint on the wall?

Physics

1 answer:

Flura [38]2 years ago

6 0

Answer:

Explanation:

1 gal = 231 in³

231 in³ (2.54³ cm³/in³) = 3,785.411784 cm³

3,785.411784 cm³ (0.01³ m³/cm³) = 0.003785411784 m³

0.003785411784 m³ / 25 m² = 0.00015141647136 m

or approximately 0.15 mm

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For a ∆x of 0.1mm, what is ∆px, the uncertainty in the transverse momentum of a photon passing through a slit (where uncertainty

Colt1911 [192]

Answer:

$0.53\times 10^{-30}kgms^{-1}$

Explanation:

Uncertainty principle say that the position and momentum can not be measured simultaneously except one relation which is described below,

$\Delta x\Delta p=\frac{h}{4\pi }$

Given that the uncertainty in x is 0.1 mm.

Therefore,

$\Delta p=\frac{6.626\times 10^{-34} }{4\times 3.14\times 1\times 10^{-4}m }\\\Delta p=0.53\times 10^{-30}kgms^{-1}$

Therefore, uncertainty in the transverse momentum of photon is $0.53\times 10^{-30}kgms^{-1}$

6 0

2 years ago

Which of the following quantities are unknown?

Sauron [17]

Answer:

Charge of the alpha particle

Explanation:

6 0

2 years ago

The mass of M1 = 12 Daltons and it has a speed of v1 = 200 m/s. The mass of M2 = 4 Daltons. What was the total momentum of the s

svet-max [94.6K]

Answer:

The total momentum is $p__{T }} =(2400 -4 v_2) \ Dalton \cdot m/s$

Explanation:

The diagram illustration this system is shown on the first uploaded image (From physics animation)

From the question we are told that

The mass of the first object is $M_1 = 12 \ Dalton$

The speed of the first mass is $v_1 = 200 \ m/s$

The mass of the second object is $M_2 = 4 \ Dalton$

The speed of the second object is assumed to be $- v_2$

The total momentum of the system is the combined momentum of both object which is mathematically represented as

$p__{T }} = M_1 v_1 + M_2 v_2$

substituting values

$p__{T }} = 12 * 200 + 4 * (-v_2)$

$p__{T }} =(2400 -4 v_2) \ Dalton \cdot m/s$

7 0

2 years ago

Calculate the work done by a 50.0 N force on an object as it moves 9.00 m, if the force is oriented at an angle of 135° from the

aivan3 [116]

Answer:

Work done, W = -318.19 Joules

Explanation:

It is given that,

Force acting on the object, F = 50 N

Distance covered by the force, d = 9 m

Angle between the force and the distance traveled, $\theta=135^{\circ}$

The work done by an object is equal to the product of force and distance traveled. It is equal to the dot product of force and the distance. Mathematically, it is given by :

$W=Fd\ cos\theta$

$W=50\times 9\times \ cos(135)$

W = -318.19 Joules

So, the work done by the force is 318.19 Joules. The work is done in opposite to the direction of motion. Hence, this is the required solution.

7 0

2 years ago

A gyroscope slows from an initial rate of 49.3 rad/s at a rate of 0.731 rad/s^2. (a) How long does it take (in s) to come to res

olasank [31]

Answer:

(a) 67.44 second

(b) 529.5 revolutions

Explanation:

ωo = 49.3 rad/s

α = 0.731 rad/s^2

(a) Let it takes t time to come to rest.

ω = 0

Use first equation of motion for rotational motion

ω = ωo + α t

0 = 49.3 - 0.731 x t

t = 67.44 second

(b) Let it turns an angle θ rad before coming to rest. use third equation of motion for rotational motion.

ω^2 = ωo^2 + 2 α θ

0 = 49.3 x 49.3 - 2 x 0.731 x θ

2430.49 = 1.462 θ

θ = 1662.44 rad

Number of revolutions = θ / 2π = 1662.44 / 3.14 = 529.5 revolutions

6 0

3 years ago

One gallon of paint covers an area of 25 m2. What is the thickness of the paint on the wall?​

One gallon of paint covers an area of 25 m2. What is the thickness of the paint on the wall?