Answer:
Explanation:
m = 0.5 kg
A = 0.15 m
vmax = 1.25 m/s
vmax = ω x A
1.25 = ω x 0.15
ω = 8.33 rad/s
(a) Let the spring constant be k
k = ω² m = 8.33 x 8.33 x 0.5 = 34.7 N/m
(b) Maximum acceleration, a max = ω² A = 8.33 x 8.33 x 0.15 = 10.42 m/s^2
(c) Let f be the frequency
ω = 2 π f
8.33 = 2 x 3.14 x f
f = 1.326 Hz
(d) Total energy
E = 1 /2 m x ω² x A² = 0.5 x 0.5 x 8.33 x 8.33 x 0.15 x 0.15 = 0.39 J
Answer:
Either B or D. The answer itself is 2.
Explanation:
The equation for the kinetic energy would be 1/2*mv^2.
When m is doubled, we can plug in 1 and 2 to compare our answers.
Plugging in 1 for mass would give us the answer 1/2*v^2.
Plugging in 2 for mass would give us v^2. This means that the velocity was multiplied by 2, meaning that the answer is it is multiplied by 2.
I am not sure which answer is correct since there seems to be two answer choices with 2 in it, but the answer is either B or D (I will call it ABCD because I do not want to cause confusion by saying 2 multiple times).
Answer:
Torque is 93 Nm anticlockwise.
Explanation:
We have value of torque is cross product of position vector and force vector.
A force of 38 N, directed 30° above the x axis in the x-y plane.
Force, F = 38 cos 30 i + 38 sin 30 j = 32.91 i + 19 j
A particle is located on the x axis 4.9 m and we have to find torque about the origin on the particle.
Position vector, r = 4.9 i
Torque, T = r x F = 4.9 i x (32.91 i + 19 j) = 4.9 x 19 k = 93.1 k Nm
So Torque is 93 Nm anticlockwise.
The tension in the cable is 169.43 N and the vertical component of the force exerted by the hi.nge on the beam is 114.77 N.
<h3>Tension in the cable</h3>
Apply the principle of moment and calculate the tension in the cable;
Clockwise torque = TL sinθ
Anticlockwise torque = ¹/₂WL
TL sinθ = ¹/₂WL
T sinθ = ¹/₂W
T = (W)/(2 sinθ)
T = (29 x 9.8)/(2 x sin57)
T = 169.43 N
<h3>Vertical component of the force</h3>
T + F = W
F = W - T
F = (9.8 x 29) - 169.43
F = 114.77 N
Thus, the tension in the cable is 169.43 N and the vertical component of the force exerted by the hi.nge on the beam is 114.77 N.
Learn more about tension here: brainly.com/question/24994188
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Thermal energy (any word that begins with therm has to do with heat)