The correct answer is options c and e.
A solid solution is basically a multi-component framework that comprises a mixture of two or more elements exhibiting a similar crystal lattice. The examples of solid solutions are alloys.
The requirements for one kind of atom to substitute for another in a solid solution are:
1. The size of the atom must be similar.
2. The substituting atom must be from a similar group.
When the formation of a substance is negative, it means that it releases heat to the surroundings. When
it releases heat to the surroundings, the reaction is exothermic. When it absorbs heat from the surroundings, the reaction is endothermic.
Answer:
λ = 0.5×10⁻⁵ m
E = 39.78×10⁻²¹ J
The given radiation is gamma ray.
Explanation:
Given data:
Frequency of radiation = 6.0 ×10¹³ Hz
Wavelength of radiation = ?
Type of radiation = ?
Energy of radiation = ?
Solution:
Formula:
speed of light = wavelength × frequency
3 ×10⁸ m/s = λ × 6.0 ×10¹³ Hz
Hz = s⁻¹
λ = 3 ×10⁸ m/s / 6.0 ×10¹³ s⁻¹
λ = 0.5×10⁻⁵ m
Energy of radiation:
E = hf
h = planck's constant
f = frequency
E = 6.63×10⁻³⁴ j.s × 6.0 ×10¹³ s⁻¹
E = 39.78×10⁻²¹ J
The given radiation is gamma ray.
Answer:
See explanation.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to firstly recall the electron configuration of hydrogen:
To realize that the principal quantum number is 1, the angular is 0 as well as the magnetic one; therefore we infer that all the given n's are not allowed, just l=0 is allowed as well as ml=0 yet the rest, are not allowed.
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Answer: 72.93 litres
Explanation:
Given that:
Volume of gas (V) = ?
Temperature (T) = 24.0°C
Convert 24.0°C to Kelvin by adding 273
(24.0°C + 273 = 297K)
Pressure (P) = 1.003 atm
Number of moles (n) = 3 moles
Molar gas constant (R) is a constant with a value of 0.0821 atm L K-1 mol-1
Then, apply ideal gas equation
pV = nRT
1.003 atm x V = 3.00 moles x 0.0821 atm L K-1 mol-1 x 297K
1.003 atm•V = 73.15 atm•L
Divide both sides by 1.003 atm
1.003 atm•V/1.003 atm = 73.15 atm•L/1.003 atm
V = 72.93 L
Thus, the volume of the gas is 72.93 litres
