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Feliz [49]
3 years ago
9

if a four engine jet accelerates down the runway at 2.0m/s^2 and one of its engines suddenly fails how much acceleration will th

e remaining three produce
Physics
1 answer:
yaroslaw [1]3 years ago
6 0

If one of the four engines suddenly fail, so this means that we only get 3 / 4 of the original force. Since force is the product of mass and acceleration and mass is constant, therefore we get 3 / 4 of the original acceleration.

So the remaining acceleration is:

a = (2.0 m/s^2) * (3 / 4)

<span>a = 1.5 m/s^2</span>

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Three objects move with a velocity of 1 m/s what is the total kinetic energy of the system?
frutty [35]
The total kinetic energy of the system is 2.5J
6 0
3 years ago
A child pulls a wagon with a force F at an angle o with respect to the horizontal. Which of the following free body diagrams is
NeTakaya

Option d) is the correct free body diagram.

Explanation:

A free-body diagram is a diagram that shows all the forces acting on a body. Each force is represented using an arrow, where:

- The length of the arrow is proportional to the magnitude of the force

- The direction of the arrow corresponds to the direction of the force

For the block in this problem, we have the following forces:

- The force F applied from the child, which acts at an angle with respect to the horizontal --> this rules out option a) and c), where the force acts horizontally

- The force of gravity (the weight of the object), labelled with W, which always acts downward --> this rules out option b), since the weight acts downward.

Therefore, the correct option is d).

(in reality, there should be another force: the normal reaction exerted by the floor on the block, N, acting upward).

Learn more about forces and weight:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

5 0
4 years ago
3. The Jupiter orbits the sun. What is the orbital speed and period?
Delicious77 [7]
The answer to your question is 77.3
5 0
3 years ago
An amusement park ride consists of a large vertical cylinder that spins about its axis fast enough that a person inside is stuck
ElenaW [278]

Let N be the normal force that forces the person against the wall.

Then u N = m g  is the frictional force supporting the person's weight

and N = m g / u

also, N = m v^2 / R is the normal force providing the centripetal acceleration

So, m g / u = m v^2 / R

v^2 = g R / u

since v = 2 pi R T

4 pi^2 R^2 T^2 = g R / u     and T^2 = g / (4  u pi^2 R)

T = 1/ (2 pi)  (g /(u R))^1/2 = .159 * (9.8 m/s^2 / (.521 * 4.4 m)) ^1/2

T = .68 / s

Do you see any thing wrong here?

T should have units of seconds not 1 / seconds

v should be  2 * pi * R / T  where T is the time for 1 revolution

So you need to make that correction in the above formula for v.

7 0
3 years ago
Please answer these, I’m willing to give plenty of points.
LUCKY_DIMON [66]

Answer:

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Explanation:

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6 0
3 years ago
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