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pishuonlain [190]
3 years ago
14

An amusement park ride consists of a large vertical cylinder that spins about its axis fast enough that a person inside is stuck

to the wall and does not slide down when the floor drops away. The acceleration of gravity is 9.8 m/s 2 . Given g = 9.8 m/s 2 , the coefficient µ = 0.521 of static friction between a person and the wall, and the radius of the cylinder R = 4.4 m. For simplicity, neglect the person’s depth and assume he or she is just a physical point on the wall. The person’s speed is v = 2πR T where T is the rotation period of the cylinder (the time to complete a full circle). Find the maximum rotation period T of the cylinder which would prevent a 40 kg person from falling down. Answer in units of s.
Physics
1 answer:
ElenaW [278]3 years ago
7 0

Let N be the normal force that forces the person against the wall.

Then u N = m g  is the frictional force supporting the person's weight

and N = m g / u

also, N = m v^2 / R is the normal force providing the centripetal acceleration

So, m g / u = m v^2 / R

v^2 = g R / u

since v = 2 pi R T

4 pi^2 R^2 T^2 = g R / u     and T^2 = g / (4  u pi^2 R)

T = 1/ (2 pi)  (g /(u R))^1/2 = .159 * (9.8 m/s^2 / (.521 * 4.4 m)) ^1/2

T = .68 / s

Do you see any thing wrong here?

T should have units of seconds not 1 / seconds

v should be  2 * pi * R / T  where T is the time for 1 revolution

So you need to make that correction in the above formula for v.

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6 0
3 years ago
Read 2 more answers
A 250 g object is hung onto a spring. It stretches 18 cm. Find the spring's spring constant
Juliette [100K]
<h2>Answer: 13.61 N/m</h2>

Hooke's law establishes that the elongation of a spring is directly proportional to the modulus of the force F applied to it, <u>as long as the spring is not permanently deformed</u>:

F=k (x-x_{o})    (1)

Where:

k is the elastic constant of the spring. The higher its value, the more work it will cost to stretch the spring.

x_{o} is the length of the spring without applying force.

x is the length of the spring with the force applied.

According to this, we have a spring where only the force due gravity is applied.

In other words, the force applied is the weigth W of the block:

W=m.g   (2)

Where m=250g=0.25kg is the mass of the block and g=9.8\frac{m}{s^{2}}  is the gravity acceleration.

W=(0.25kg)(9.8\frac{m}{s^{2}})   (3)

W=2.45N   (4)

Knowing the force applied W and x=18cm=0.18m and x_{o}=0, we can substitute the values in equation (1) and find k:

W=k (x-x_{o})    (5)

2.45N=k (0.18m-0m)    (6)

<u>Finally:</u>

k=13.61\frac{N}{m}  

4 0
3 years ago
Which jovian planet should have the most extreme seasonal changes? a. Saturn b. Neptune c. Jupiter d. Uranus
Maksim231197 [3]

Answer:

D). Uranus.

Explanation:

Jovian planets are described as the planets which are giant balls of gases and located farthest from the sun which primarily include Jupiter, Saturn, Uranus, and Neptune.

As per the question, 'Uranus' is the jovian planet that would have the most extreme seasonal changes as its tilted axis leads each season to last for about 1/4 part of its 84 years orbit. The strong tilted axis encourages extreme changes in the season on Uranus. Thus, <u>option D</u> is the correct answer.

3 0
3 years ago
An iron railroad rail is 700 ft long when the temperature is 30°C. What is its length when the temperature is – 10°C?
MAVERICK [17]

Answer:

699.67ft

Explanation:

We are given with,

  • α = 1.2×10⁻⁵ / °C
  • L₀ = 700 ft
  • ΔT = -10°C − 30°C = -40°C

Now, We have to find ΔL:

  • ΔL = (1.2×10⁻⁵ / °C) (700 ft) (-40°C)
  • ΔL = −0.336

Rounded to two significant figures, the change in length is −0.33ft.

<u>Therefore, the final length is approximately 700 ft − 0.33 ft = 699.67ft</u>.

6 0
3 years ago
What is the difference between kinetic energy and potential energy​
uranmaximum [27]

Answer:

Kinetic energy is the energy of a moving body while potential energy is the energy by vutue of it's position

8 0
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