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ira [324]
3 years ago
10

1) What kind of energy is gained when your roller coaster goes uphill?

Physics
2 answers:
kolbaska11 [484]3 years ago
7 0
The answer for the first question - increasing of potential energy (as a result of  the gravitation field)
The second : when the roller coaster gets upwards it becomes slower a bit and while potential energy is being increased, the kinetic one is getting lower. Do not forget that the sum of these energies is always constant.

Dvinal [7]3 years ago
4 0

1) Gravitational potential energy

In fact, gravitational potential energy is given by: GPE=mgh

where m is the mass of the roller coaster, g is the gravitational acceleration and h is the heigth. Therefore, when the roller coaster goes uphill, the height h increases and the roller coaster gains gravitational potential energy.

2) The relationship between potential and kinetic energy is:

M.E.=K.E.+G.P.E.

where ME is the total mechanical energy, KE is the kinetic energy, GPE is the gravitational potential energy. Since the value of ME is constant (when no friction is present), this means that when KE increases, GPE decreases, and vice-versa.

3) If friction is removed from the track, the roller coaster would move forever. In fact, in the equation written in part 2), ME is constant only in case there is no friction - when friction is present, part of the energy is lost due to the friction, so the total ME available decreases little by little until it becomes zero, and the roller coaster cannot move anymore.

4) It matters because it affects the magnitude of the friction. In fact, friction is given by

F=\mu mg

where \mu is the coefficient of friction, m is the mass ,and g the gravitational acceleration. When the number of carts is increased, the mass increases, therefore the friction increases as well.

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An object is thrown with a horizontal velocity of 49.0 mt/sec and a vertical velocity 18.8 mt/sec. How long with the object take
UNO [17]

Answer:

49.0 x18.8 ur answer i think

Explanation:

7 0
3 years ago
Read 2 more answers
A 200kg bumper car moving 3 m/s collides head on with a 392kg bumper car moving 6m/s. After impact, the larger car continues tra
Maru [420]

Answer:

the final speed of the smaller car is 5.624 m/s

Explanation:

Given;

mass of the small car, m₁ = 200 kg

initial velocity of the small car, u₁ = 3 m/s

mass of the larger car, m₂ = 392 kg

initial velocity of the larger car, u₂ = 6 m/s

final velocity of the larger car, v₂ = 1.6 m/s

let the direction of the larger car be positive

let the direction of the smaller car be negative

Apply the principle of conservation of linear momentum to determine the final speed of the smaller car.

m₁u₁ + m₂u₂ = m₁v₁  +  m₂v₂

200(-3)  +  392(6)  = 200v₁   +  392 x 1.6

-600 + 2352  = 200v₁    +  627.2

1752   =  200v₁     +   627.2

1752  -  627.2     =  200v₁

1124.8  = 200v₁

v₁  =  1124.8/200

v₁ = 5.624 m/s

Therefore, the final speed of the smaller car is 5.624 m/s

7 0
3 years ago
At the start of a hockey game, the referee drops the puck between two players from opposing teams. Each player wants to push the
spin [16.1K]

Answer:

a) puck is subjected to both the forces of the hockey sticks in a horizontal direction,

b)the puck does not move since the sum of the forces is zero

c) changing the magnitude or direction of its applied force

Explanation:

a) The puck is subjected to both the forces of the hockey sticks in a horizontal direction, these forces are of equal magnitude and opposite direction since the puck is at rest.

In the direction of the y-axis (perpendicular to the ice) you have the weight of the disk and the normal to this weight that are also in equilibrium.

b) the puck does not move since the sum of the forces is zero, which implies that the forces of the hockey sticks are of equal magnitude and opposite direction.

c) the player has several ways to make the puck move

* slightly changing the angle of the club and therefore the direction of the force, in this case the disc comes out in the direction of this component

* inclined the stick slightly so that the force has a vertical component and the puck jumps in this direction

* Increasing the magnitude of the force so that the puck comes out in the opposite direction to the player

* The worst case, decreasing its force to zero and the disk comes out in its direction by the other force that had the same magnitude.

3 0
4 years ago
A 1.8 kg book has been dropped from the top of the football stadium. Its speed is 4.8 m/s when it is 2.9 meters above the ground
Alexus [3.1K]

Answer:

Answer:

72.936 Joule

Explanation:

Mechanical Energy = Potential Energy + Kinetic Energy

Kinetic Energy = (1/2) x m x V² = (1/2) x 1.8 x 4.8² = 20.736 J

Potential Energy = m x g x h = 1.8 x 10 x 2.9 = 52.2 J

Total Mechanical Energy = 20.736 + 52.2 = 72.936 Joule

Explanation:

8 0
3 years ago
The initial concentration of acid ha in solution is 0.39 m. if the ph of the solution at equilibrium is 0.76, what is the percen
Alexus [3.1K]

The percent ionization of the acid is 44.56%

<h3>How can we calculate the percent ionization of the acid?</h3>

To calculate the percent ionization of the acid we are using the formula,

The H⁺ ion concentration [H⁺] = C x,

where, we are given,

C= concentration of the acid.

=0.39 M

x= degree of dissociation of the acid.

And one more thing we are given that, the pH of the acid=0.76.

So from the above statement we can say that,

pH = - log [H⁺]

Or,0.76 = -log [H⁺]

Or, log [H⁺] = -0.76

Or, [H⁺] = antilog -0.76

Or,[H⁺]= 10^-0.76

Or,[H⁺]=0.1738.

Now from the above calculation we know, the H⁺ ion concentration= 0.1738 M.

Now we put the known values in the above equation,

[H+]= Cx

Or,0.1739= 0.39 x

Or, x= 0.4459

From the above calculation we can conclude that the percent Ionization of the acid= 0.4459 X 100= 44.59%≈45%

Learn more about Ionization:

brainly.com/question/1445179

#SPJ4

4 0
1 year ago
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