1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ira [324]
3 years ago
10

1) What kind of energy is gained when your roller coaster goes uphill?

Physics
2 answers:
kolbaska11 [484]3 years ago
7 0
The answer for the first question - increasing of potential energy (as a result of  the gravitation field)
The second : when the roller coaster gets upwards it becomes slower a bit and while potential energy is being increased, the kinetic one is getting lower. Do not forget that the sum of these energies is always constant.

Dvinal [7]3 years ago
4 0

1) Gravitational potential energy

In fact, gravitational potential energy is given by: GPE=mgh

where m is the mass of the roller coaster, g is the gravitational acceleration and h is the heigth. Therefore, when the roller coaster goes uphill, the height h increases and the roller coaster gains gravitational potential energy.

2) The relationship between potential and kinetic energy is:

M.E.=K.E.+G.P.E.

where ME is the total mechanical energy, KE is the kinetic energy, GPE is the gravitational potential energy. Since the value of ME is constant (when no friction is present), this means that when KE increases, GPE decreases, and vice-versa.

3) If friction is removed from the track, the roller coaster would move forever. In fact, in the equation written in part 2), ME is constant only in case there is no friction - when friction is present, part of the energy is lost due to the friction, so the total ME available decreases little by little until it becomes zero, and the roller coaster cannot move anymore.

4) It matters because it affects the magnitude of the friction. In fact, friction is given by

F=\mu mg

where \mu is the coefficient of friction, m is the mass ,and g the gravitational acceleration. When the number of carts is increased, the mass increases, therefore the friction increases as well.

You might be interested in
Express newton pascal joule and watt in fundamental unit​
Nadya [2.5K]

i added an image. i hope it helped :)

3 0
3 years ago
The core of a star must be at temperature of _____ degrees Celsius for hydrogen fusion to take place. 10,000 100,000 1,000,000 1
disa [49]
The core of a star must be at the temperature of 10,000,000 degrees Celsius for hydrogen fusion to begin. 
6 0
3 years ago
At take off, a plane flies 100 km north before turning to fly 200 km east. How far is its destination from where the plane took
Snowcat [4.5K]
The answer is 300 km

To the destination
4 0
3 years ago
For states with larger values of n that admit a d subshell, the d subshell is at even higher energy than the p subshell. In fact
frosja888 [35]

Answer:

Explanation:

Correct order of energy of energy states within an atom is as follows

1s , 2 s, 2 p 3 s ,3 p, 4s , 3d,  4p, 4p,5s etc.

There is discrepancies in this order due to overlapping of outer orbitals with inner orbitals so sometimes outer orbitals have lower energy.

4 0
3 years ago
Three point charges are arranged along the x axis. Charge q1=-4.00nC is located at x= .250 m and q2= 2.40 nC is at the x= -.300m
Umnica [9.8K]

Answer:

q₃=5.3nC

Explanation:

First, we have to calculate the force exerted by the charges q₁ and q₂. To do this, we use the Coulomb's Law:

F= k\frac{|q_aq_b|}{r^{2} } \\\\\\F_{13}=(9*10^{9} Nm^{2} /C^{2} )\frac{|(-4.00*10^{-9}C)q_3|}{(.250m)^{2} } =576q_3N/C\\\\F_{23}=(9*10^{9} Nm^{2} /C^{2} )\frac{|(2.40*10^{-9}C)q_3|}{(.300m)^{2} } =240q_3N/C\\

Since we know the net force, we can use this to calculate q₃. As q₁ is at the right side of q₃ and q₁ and q₃ have opposite signs, the force F₁₃ points to the right. In a similar way, as q₂ is at the left side of q₃, and q₂ and q₃ have equal signs, the force F₂₃ points to the right. That means that the resultant net force is the sum of these two forces:

F_{Net}=F_{13}+F_{23}\\\\4.40*10^{-9} N=576q_3N/C+240q_3N/C\\\\4.40*10^{-6} N=816q_3N/C\\\\\implies q_3=5.3*10^{-9}C=5.3nC

In words, the value of q₃ must be 5.3nC.

7 0
3 years ago
Other questions:
  • A 1.4-µC point charge is placed between the plates of a parallel plate capacitor. The charge experiences a force of 0.38 N. What
    7·1 answer
  • What group tend to take on electrons in order to become stable
    13·1 answer
  • Lucas plugs a lamp into the wall. The light bulb in the lamp turns on. What kind of energy transformation is this? A.)Light ener
    9·2 answers
  • Calculate the gravitational potential energy of the interacting pair of the Earth and a 11 kg block sitting on the surface of th
    10·1 answer
  • For each of the
    14·1 answer
  • When an object oscillating in simple harmonic motion is at its maximum displacement from the equilibrium position, which of the
    15·1 answer
  • A battery with an emf of 4 V and an internal resistance of 0.7 capital omega is connected to a variable resistance R. Find the c
    15·1 answer
  • A heliocentric system is _____-centered.<br><br> Milky Way<br> Earth<br> Moon<br> Sun
    11·2 answers
  • If the initial speed of the ball was increased, the time of flight of the ball would
    11·1 answer
  • HELP DUE 3 MINUTESSSSD
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!