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labwork [276]
4 years ago
11

A child pulls a wagon with a force F at an angle o with respect to the horizontal. Which of the following free body diagrams is

correct?

Physics
1 answer:
NeTakaya4 years ago
5 0

Option d) is the correct free body diagram.

Explanation:

A free-body diagram is a diagram that shows all the forces acting on a body. Each force is represented using an arrow, where:

- The length of the arrow is proportional to the magnitude of the force

- The direction of the arrow corresponds to the direction of the force

For the block in this problem, we have the following forces:

- The force F applied from the child, which acts at an angle with respect to the horizontal --> this rules out option a) and c), where the force acts horizontally

- The force of gravity (the weight of the object), labelled with W, which always acts downward --> this rules out option b), since the weight acts downward.

Therefore, the correct option is d).

(in reality, there should be another force: the normal reaction exerted by the floor on the block, N, acting upward).

Learn more about forces and weight:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

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The cylindrical tub of a dryer in a laundromat rotates counterclockwise about a horizontal axis at 41.5 rev/min as it dries the
frozen [14]

Answer:

\theta = 49.81^0

Explanation:

Given that:

\omega = 41.5 \ rev/min\\\\\omega = 41.5 *\frac{1}{60}* 2 \pi\\\\\omega = 4.45 \ rad/s\\\\\\diameter = 0.748 m

If we let the piece of the close lose contact at ∠θ;

Then ; from force balance;

we have:

\\\\mg sin \theta = \frac{mv^2}{r}\\\\sin \theta = \frac{2v^2}{dg}\\\\\theta = sin^{-1} (\frac{2v^2}{dg})

where;

v = \frac{\omega d}{2}\\\\v =  \frac{4.45 *0.748}{2}\\\\v = 1.6643\\\\v^2 = 2.77

Again:

\theta = sin^{-1}(\frac{2v^2}{dg})\\\\\theta = sin^{-1}( \frac{2*2.77}{0.74*9.8})\\\\\theta = 49.81^0

6 0
3 years ago
What is the basis for rutherford's planetary model?
Olenka [21]
The basis for Rutherford's Planetary model, was the results he got from experiments.

He observed that most of the alpha particles he fired at a gold foil, passed through the foil, but only few were deflected back. So he concluded that most of the Atom would be empty space, with a positive entity at the center.
3 0
3 years ago
As an electron approaches a proton, the electron's force of attraction...
Tems11 [23]

Answer: B. Increases

Explanation:

An electron is a negatively charged particle, while a proton is positively charged.

Opposites attract so as it approaches the proton the force of attraction will increase.

7 0
3 years ago
J-s. If your 1400-kg car is parked in an 8.54-m-long garage, what is the uncertainty in its velocity? cm/s the tolerance is +/-2
IgorC [24]

Answer:

\Delta v = 4.41 \times 10^{-37} cm/s

Explanation:

As per Heisenberg's uncertainty principle we know that

\Delta P \times \Delta x = \frac{h}{4\pi}

so here we have

\Delta P = m\Delta v

\Delta x = 8.54 m

now from above equation we have

m\Delta v \times (8.54) = \frac{h}{4\pi}

1400(\Delta v) \times (8.54) = \frac{6.626 \times 10^{-34}}{4\pi}

\Delta v = 4.41 \times 10^{-39} m/s

\Delta v = 4.41 \times 10^{-37} cm/s

8 0
3 years ago
What does an atom look like under an electron microscope?
ratelena [41]
If you look at a atom under a electron microscope you would use it
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