Answer:
The correct answer is 0.36 mol
Explanation:
First we have to calculate the molecular weight (Mw) of H₃BO₃ from the molar masses of the elements:
Mw(H₃BO₃)= 3 x Molar mass H + Molar mass B + (3 x Molar mass O)
= 3 x 1 g/mol + 10.8 g/mol + (3 x 16 g/mol)
= 61.8 g/mol
The molecular weight indicates that there are 61.6 grams per mol of substance. The scientist has 22.5 g, thus we can calculate the number of moles of H₃BO₃ by dividing the mass into the molecular weight as follows:
Number of moles of H₃BO₃ = mass/Mw= (22.5 g)/(61.8 g/mol) = 0.36 mol
There are 0.36 mol of H₃BO₃ in 750.0 mL of solution.
Answer:
0.1388 g
Explanation:
The mass of
obtained on precipitation = 236 mg
1 mg = 0.001 g
Thus, Mass of
= 0.236 g
Molar mass of
= 233.43 g/mol
The formula for the calculation of moles is shown below:
Thus,
Moles of
= 0.001011 moles
According to the reaction,

Thus, moles of barium = 0.001011 moles
Molar mass of barium = 137.327 g/mol
Thus, Mass = Moles * Molar mass = 0.001011*137.327 g = 0.1388 g
Answer:
In these two-letter symbols, the first letter is always capitalized and the second is always lowercased.
Answer:
Prokaryotic is the answer!
Explanation:
I know this because, the nucleolus is absent in the image.
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Answer:
Explanation:
2. a [CO3 2-][H3O+] / [H2O][HCO3-
b. [H2PO4-][H3O+]/[H3PO4][H2O]