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sukhopar [10]
3 years ago
7

Examples of food types that contain potential energy

Chemistry
1 answer:
Marrrta [24]3 years ago
3 0

Answer:

Organic vitamens

Explanation:

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What are the units of k in the following rate law?
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B. \frac{1}{M^{2} s }

Explanation:

The unit for rate is M/s while the unit for each molecule should be M. You can find the unit for k by putting the units for rate and the molecules into the equation

rate= k{X][Y]

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k= (M/s) / (M^{3})

k= \frac{1}{M^{2} s }

You can also use this predetermined formula to solve this problem faster: k= \frac{M^{1-n} }{s }

Where n is the number of molecule. There are 3 molecule(2X and 1Y) so n=3, so

k= \frac{M^{1-n} }{s }

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