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3 years ago

List and define three types of intermolecular forces and identify which types of molecules each forces affects.

Physics

1 answer:

Zigmanuir [339]3 years ago

3 0

Van der waals forces

Hydrogen bonding

Crystal lattice forces

Explanation:

Intermolecular forces exists between molecules.

Van der waals forces are weak attractions that joins non-polar and polar molecules together. London dispersion forces occurs between non-polar molecules(polar) and noble gases. Dipole -dipole attraction occurs between polar molecules. Van der waal forces occurs in graphite layers, HCl e.t.c
Hydrogen bonding is force of attraction between polar molecules in which a hydrogen atom is directly joined to a highly electronegative atom. Examples occur in water.
Ionic crystal lattice forces are strong electrostatic forces of attraction between oppositely charged ions arranged into a crystal lattice of ionic compounds. For example in NaCl

Learn more:

Intermolecular forces brainly.com/question/3622116

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a. 2.00kg object is subject to three force that gives acceleration a =8m/s^2 i +6m/s j if two of three forces are f1 =(30.0N)+(1

tekilochka [14]

By Newton's second law, the net force on the object is

∑ F = m a

∑ F = (2.00 kg) (8 i + 6 j ) m/s^2 = (16.0 i + 12.0 j ) N

Let f be the unknown force. Then

∑ F = (30.0 i + 16 j ) N + (-12.0 i + 8.0 j ) N + f

=> f = (-2.0 i - 12.0 j ) N

8 0

3 years ago

One end of a 34-m unstretchable rope is tied to a tree; the other end is tied to a car stuck in the mud. The motorist pulls side

anyanavicka [17]

Answer:

Fc = 89.67N

Explanation:

Since the rope is unstretchable, the total length will always be 34m.

From the attached diagram, you can see that we can calculate the new separation distance from the tree and the stucked car H as follows:

L1+L2=34m

$L1^2=L2^2=L^2=2^2+(H/2)^2$ Replacing this value in the previous equation:

$\sqrt{2^2+H^2/4}+ \sqrt{2^2+H^2/4}=34$ Solving for H:

$H=\sqrt{52}$

We can now, calculate the angle between L1 and the 2m segment:

$\alpha = atan(\frac{H/2}{2})=60.98°$

If we make a sum of forces in the midpoint of the rope we get:

$-2*T*cos(\alpha ) + F = 0$ where T is the tension on the rope and F is the exerted force of 87N.

Solving for T, we get the tension on the rope which is equal to the force exerted on the car:

$T=Fc=\frac{F}{2*cos(\alpha) } = 89.67N$

7 0

3 years ago

A car moved 60 meters west in 2 hours. What is its average velocity?

Fofino [41]

Explanation: Velocity is the displacement of an object during a specific unit of time. Two measurements are needed to determine velocity. Displacement and time. Displacement includes a direction, so velocity also includes a direction. Speed with direction. Velocity can be an average velocity or an instantaneous velocity. Units for velocity are the same as for speed: m/s, km/h, and mph. Delta x(Δx) is the symbol used for displacement. Delta (Δ) means to "change in." Δx means to "change in position." Δx is calculated by final position minus initial position. Velocity formula: → v=Δx/t as a fraction.

v=Δx/t

$v=\frac{xf-xi}{t}= \frac{60m}{2}=30m$

Final answer is 30.

Hope this helps!

Thanks!

Have a great day!

-Charlie

5 0

2 years ago

A spring with spring constant 33N/m is attached to the ceiling, and a 4.8-cm-diameter, 1.5kg metal cylinder is attached to its l

mylen [45]

Answer:

0.423m

Explanation:

Conversion to metric unit

d = 4.8 cm = 0.048m

Let water density be $\who_w = 1000 kg/m^3$

Let gravitational acceleration g = 9.8 m/s2

Let x (m) be the length that the spring is stretched in equilibrium, x is also the length of the cylinder that is submerged in water since originally at a non-stretching position, the cylinder barely touches the water surface.

Now that the system is in equilibrium, the spring force and buoyancy force must equal to the gravity force of the cylinder. We have the following force equation:

$F_s + F_b = W$

Where $F_s = kx$ N is the spring force, $F_b = W_w = m_wg = \rho_w V_s g$ is the buoyancy force, which equals to the weight $W_w$ of the water displaced by the submerged portion of the cylinder, which is the product of water density $\rho_w$ , submerged volume $V_s$ and gravitational constant g. W = mg is the weight of the metal cylinder.

$kx + \rho_w V_s g = mg$

The submerged volume would be the product of cross-section area and the submerged length x

$V_s = Ax = \pi(d/2)^2x$

Plug that into our force equation and we have

$kx + \rho_w \pi(d/2)^2x g = mg$

$x(k + \rho_w g \pi d^2/4) = mg$

$x = \frac{m}{(k/g) + (\rho_w\pi d^2/4)} = \frac{1.5}{(33/9.8) + (100*\pi * 0.048^2/4)} = 0.423 m$

6 0

2 years ago

One significant result of the Michelson experiment of 1880 was that it:

Alika [10]

Answer:

calculated the speed of light over a short distance

Explanation:

Albert Michelson was an American physicist who conducted an experiment regarding the speed of light in the air 1880s. He believed in the existence of "aether," a field of space that is deemed necessary for transporting electromagnetic forces. In order to do this, he setup a device in order to accurately measure the speed of light in in aether. His device is now known as "Michelson interferometer." The result was actually negative. 

In order to make his experiment even more accurate, he collaborated with Edward Morley, a famous American scientist. Although the result failed, together, they were able to improve and come with the a standard length of light. This calculated the speed of light over a short distance, which was the significant result of Michelson's experiment.

Thus, this explains the answer.

8 0

2 years ago

Read 2 more answers