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lbvjy [14]
3 years ago
8

List and define three types of intermolecular forces and identify which types of molecules each forces affects.

Physics
1 answer:
Zigmanuir [339]3 years ago
3 0

Van der waals forces

Hydrogen bonding

Crystal lattice forces

Explanation:

Intermolecular forces exists between molecules.

  • Van der waals forces are weak attractions that joins non-polar and polar molecules together. London dispersion forces occurs between non-polar molecules(polar) and noble gases. Dipole -dipole attraction occurs between polar molecules. Van der waal forces occurs in graphite layers, HCl e.t.c
  • Hydrogen bonding is force of attraction between polar molecules in which a hydrogen atom is directly joined to a highly electronegative atom. Examples occur in water.
  • Ionic crystal lattice forces are strong electrostatic forces of attraction between oppositely charged ions arranged into a crystal lattice of ionic compounds. For example in NaCl

Learn more:

Intermolecular forces brainly.com/question/3622116

#learnwithBrainly

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PLS HELP FAST!!!!!!!
Elan Coil [88]

Answer:D

Explanation:

6 0
1 year ago
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You have been assigned to investigate a traffic accident. The masses of car A and car B are 1300 kg and 1200 kg, respectively. C
jarptica [38.1K]

Answer:

The velocity of A before impact = 17.90 m/s

Explanation:

Coefficient of restitution = (speed of seperation)/(speed of approach)

= (v₁ - v₂)/(u₂ - u₁)

where v₁ = velocity of the car A after the impact = ?

v₂ = velocity of the car B after the impact = ?

u₂ = velocity of the car B before the impact = 0 m/s (it was initially at rest)

u₁ = velocity of car A before the impact = ?

First of, we can solve for v₂, the velocity of car B after the impact, from some of the information given in the question.

- Skid marks indicate car B slid 10 m after the impact

- The coefficient of kinetic friction the tires and road is 0.8.

According to the work energy theorem, the work done by frictional force in stopping the car B is equal to the change in kinetic energy of the car B. (All after collision)

W = ΔK.E

ΔK.E = (1/2)(1200)(v₂²) - 0 (final kinetic energy is 0 since the car comes to stop eventually)

ΔK.E = (600v₂²) J

W = F × d

where F = frictional force = μmg = 0.8×1300×9.8 = 10,192 N

d = distance the car skids over before stopping = 10 m

W = 10,192 × 10 = 101,920 J

W = ΔK.E

101,920 = 600v₂²

v₂² = (101920/600) = 169.867

v₂ = 13.03 m/s

But recall,

Coefficient of restitution = (v₁ - v₂)/(u₂ - u₁)

For the sake of convention, we take the direction of car A's initial velocity to be the positive direction.

u₁ = ?

u₂ = 0 m/s

v₁ = ?

v₂ = +13.03 m/s

Coefficient of restitution = 0.4

0.4 = (v₁ - 13.03)/(0 - u₁)

-0.4u₁ = v₁ - 13.03

v₁ = 13.03 - 0.4u₁

But this is a collision. In a collision, the linear momentum is usually conserved.

Momentum before collision = Momentum after collision

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

1300u₁ + (1200×0) = 1300v₁ + (1200×13.03)

1300u₁ + 0 = 1300v₁ + 15639.95

1300u₁ = 1300v₁ + 15639.95

But recall, from the coefficient of restitution relation,

v₁ = 13.03 - 0.4u₁

Substituting this into the momentum balance equation.

1300u₁ = 1300v₁ + 15639.95

1300u₁ = 1300(13.03 - 0.4u₁) + 15639.95

1300u₁ = 16943.28 - 520u₁ + 15639.95

1820u₁ = 32,583.23

u₁ = (32,583.23/1820)

u₁ = 17.90 m/s

Therefore, the velocity of A before impact = 17.90 m/s

Hope this Helps!!!

4 0
4 years ago
12. your friend with great excitement tells you about his newest idea to solve the energy crisis: he wants to use an electromoto
mixas84 [53]
I would tell him, in the kindest, most gentle way I could manage,
to fahgeddaboudit. 

The total amount of energy doesn't change.  Energy is never created,
and it never disappears.  If you have some energy, then it had to come
from somewhere, and if you used some energy, then it had to go
somewhere. 

You can never get more energy out of the electromotor than you put into it,
 and in the real world, you can't even get THAT much out, because some
of it is always used on the way through.

Pour yourself a cold glass of soda, then look up "Perpetual Motion" or
"Free Energy" on the internet, relax, and enjoy the show.  They are all
fakes.  They may not all be intentionally meant to fool you, but they are
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4 0
3 years ago
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Calculate the total resistance for a 650ohm , a 350 ohm , and a 1000 ohm resistor connected in series
Mekhanik [1.2K]

Answer:

2000 ohms

Explanation:

Resisters in series just add.

Rt = R1 + R2 + R3

R1 = 650 ohm

R2 = 350 ohm

R3 = 1000 ohm

Rt = 650 + 350 + 1000

Rt = 2000 ohms.

5 0
3 years ago
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Light travels 3,00,000 km/s . Is it velocity or speed?​
Ludmilka [50]

Answer:

speed

Explanation:

according to your question, your answer is speed

7 0
3 years ago
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