Answer: (-2, 5) and (2, -3)
<u>Step-by-step explanation:</u>
Graph the line y = -2x + 1 (which is in y = mx + b format) by plotting the y-intercept (b = 1) on the y-axis and then using the slope (m = -2) to plot the second point by going down 2 and right 1 unit from the first point:
y - intercept = (0, 1) 2nd point = ( -1, 1).
Graph the parabola y = x² - 2x - 3 by first plotting the vertex and then plotting the y-intercept (or some other point):

vertex = (1, -4) 2nd point (y-intercept) = (0, -3)
<em>see attached</em> - the graphs intersect at two points: (-2, 5) and (2, -3)
I think the wrong is the answer , I hope that help , good luck
Define i as a unit vector in the eastern direction.
Define j as a unit vector in the northern direction.
Part I
Because the wind is blowing west, its velocity vector is
-23i mph or as (-23, 0) mph
Because the plane is traveling north, its velocity vector is
200j mph or as (0, 200) mph
Part II
The actual velocity of the plane is the vector sum of the plane and wind velocities.
That is,
200j - 23i or (-23, 200) mph
Part III
The ground speed of the plane is the magnitude of its vector.
The ground speed is
√[200² + (-23)²] = 201.32 mph
The ground speed of the plane is 201.3 mph (nearest tenth)
Not:
The direction of the plane is
tan⁻¹ 23/200 = 6.56° west of north.