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3 years ago

Pls help ASAP now! This is physical science

Physics

2 answers:

zalisa [80]3 years ago

7 0

Answer:

Explanation:

D and C are both eliminated because it being shaped like a horseshoe has nothing yo do with it and c is wrong cause the core is really hot there for it can not be similar so A because it has north and south poles meaning its magnetic ability

const2013 [10]3 years ago

6 0

Option A is correct answer

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A 100-g toy car is propelled by a compressed spring that starts it moving. the car follows a curved track. what is the final spe

wel

Answer:

0.687 m/s

Explanation:

Initial energy = final energy

1/2 mu² = mgh + 1/2 mv²

1/2 u² = gh + 1/2 v²

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3 years ago

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mina [271]

Which questions? i need to see the actual question, did you like upload them to your profile now?

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3 years ago

Alternating Current In Europe, the voltage of the alternating current coming through an electrical outlet can be modeled by the

stealth61 [152]

Answer:

$\frac{50}{\pi }$ Hz

Explanation:

In alternating current (AC) circuits, voltage (V) oscillates in a sine wave pattern and has a general equation as a function of time (t) as follows;

V(t) = V sin (ωt + Ф) -----------------(i)

Where;

V = amplitude value of the voltage

ω = angular frequency = 2 π f [f = cyclic frequency or simply, frequency]

Ф = phase difference between voltage and current.

Now,

From the question,

V(t) = 230 sin (100t) ---------------(ii)

By comparing equations (i) and (ii) the following holds;

V = 230

ω = 100

Ф = 0

But;

ω = 2 π f = 100

2 π f = 100 [divide both sides by 2]

π f = 50

f = $\frac{50}{\pi }$ Hz

Therefore, the frequency of the voltage is $\frac{50}{\pi }$ Hz

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3 years ago

A trombone can produce pitches ranging from 85 Hz to 660 Hz approximately. When the trombone is producing a 562 Hz tone, what is

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To solve this problem we will apply the concept of wavelength, which warns that this is equivalent to the relationship between the speed of the air (in this case in through the air) and the frequency of that wave. The air is in standard conditions so we have the relation,

Frequency $= f = 562Hz$