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shusha [124]
4 years ago
11

All of the following are regulated by the medulla except

Physics
1 answer:
Fantom [35]4 years ago
6 0

Answer:

D. flight or flight response.

Explanation:

im 99.999999% sure im right.

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Electrons are ejected from a metallic surface with speeds of up to 4.60 3 105 m/s when light with a wavelength of 625 nm is used
Darya [45]

Complete question:

Electrons are ejected from a metallic surface with speeds ranging up to 4.60 x10⁵ m/s when light with a wavelength of 625nm is used. (a) What is the work function of the surface? (b) What is the cutoff frequency for this surface?

Answer:

Part(a) The work function of the surface is 22.177 x 10⁻²⁰ J = 1.384 eV

Part(b) The cutoff frequency for this surface is 3.347 x 10¹⁴ Hz

Explanation:

The kinetic energy (KE) of the emitted photon:

KE = 0.5mv²

m is mass of electron = 9.1 X 10⁻³¹ kg

KE = 0.5 * 9.1 X 10⁻³¹  * (460000)² = 9.628 X 10⁻²⁰ J

in eV = 9.628 X 10⁻²⁰ J x 6.242 X 10¹⁸ ev = 0.601 eV

The photon energy of the incoming radiation:

E = hf = hc/λ

c is speed of light (photon) = 3 x 10⁸

h is Planck's constant = 6.626 × 10⁻³⁴ J.s

E = (6.626 × 10⁻³⁴ *3 x 10⁸) /(625 X 10⁻⁹)

E = 31.805 X 10⁻²⁰ J

in eV = 31.805 X 10⁻²⁰ J x  6.242 X 10¹⁸ ev = 1.985 eV

Part (a) the work function of the surface

KE = hf - W

where;

W is work function

W = hf - KE

W =  31.805 X 10⁻²⁰ J - 9.628 X 10⁻²⁰ J = 22.177 x 10⁻²⁰ J

in eV = 22.177 x 10⁻²⁰ J x 6.242 X 10¹⁸ ev = 1.384 eV

Part(b) the cutoff frequency for this surface

W =hf

f = W/h

f = (22.177 x 10⁻²⁰ J)/(6.626 × 10⁻³⁴ J.s)

f = 3.347 x 10¹⁴ Hz

8 0
3 years ago
What is the amount of charge a capacitor can store per volt of potential difference?
sladkih [1.3K]

The amount of charge a capacitor can store per volt of potential difference is called the capacitance of the capacitor.

<h3>What is the capacitance?</h3>

The capacitance has to do with the amount of charge that is stored by a capacitor. We know that a capacitor is a device that can be used to store electric charges. We have in it, two capacitors separated by a dielectric material.

Hence, the amount of charge a capacitor can store per volt of potential difference is called the capacitance of the capacitor.

Learn more about capacitor:brainly.com/question/17176550

#SPJ1

4 0
2 years ago
Read 2 more answers
which changes of state should she place in the column titled "lose energy"?freezing, boiling, and meltingmelting, vaporization,
Blababa [14]
Freezing (liquid to solid)
Deposition (gas to solid)
Condensation (gas to liquid)

All three of these state changes are a result of a energy loss. When considering energy loss it is best to think of situations where temperature has dropped. Less energy in the system results in less energy the substance is exposed to or has available. 
7 0
3 years ago
Read 2 more answers
A helicopter goes straight up 500m from a landing pad. It then goes north 20m. Then it goes down 452m. a) What is the displaceme
gavmur [86]

Answer:

a

  x-component             20 \  m

y-component     500 -  452 =  48 \  m

b

 Magnitude d  =  52 \  m

direction is  \theta  = 67.4^o

Explanation:

From the question we are told that

   The first  vertical distance is  y_1   = 500 \  m

    The  first horizontal distance  is  x =  20 \  m

    The  second vertical distance is  y_2  =  452 \  m

Generally the displacement is  

x-component             20 \  m

y-component     500 -  452 =  48 \  m

Generally the helicopters displacement is mathematically evaluated as  

       d  =  \sqrt{ x- component ^2  +  y- component ^2 }

      d  =  \sqrt{ 20t ^2  + 48 ^2 }

      d  =  52 \  m

The  direction is the angle the displacement of the helicopter makes with the horizontal which is mathematically evaluated as

         \theta  = tan ^{-1}[ \frac{48}{20}]

=>       \theta  = tan ^{-1}[ 2.4 ]

=>      \theta  = 67.4^o

   

3 0
3 years ago
The electron gun in an old TV picture tube accelerates electrons between two parallel plates 1.0 cm apart with a 20 kV potential
Julli [10]

Answer:

A) electric field strength between the plates;E = 2 x 10^(6) N/C

B) exit velocity;v = 8.39 x 10^(7) m/s

Explanation:

We are given;

Potential difference; V = 20 kV = 20000 V

Distance between the 2 parallel plates; d = 1cm = 0.01 m

A) The electric field strength will be gotten from;

E = V/d

E = 20000/0.01

E = 2000000

E = 2 x 10^(6) N/C

B) For exit speed, we'll use the formula for Kinetic energy; KE = (1/2)mv²

KE is also expressed as; V•q_e

Thus,

(1/2)mv² = V•q_e

Where;

V is potential difference = 20000 V

Q_e is charge of electron which has a constant value of; (1.6 x 10^(-19))C

m is mass of electron with a constant value of (9.1 x 10^(-31)) kg

v is the velocity

Thus, making v the subject, we have;

v = √((2V•q_e)/m)

v = √((2 x 20000•(1.6 x 10^(-19)))/(9.1 x 10^(-31)))

v = 83862786 m/s or

v = 8.39 x 10^(7) m/s

3 0
3 years ago
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