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shusha [124]
4 years ago
11

All of the following are regulated by the medulla except

Physics
1 answer:
Fantom [35]4 years ago
6 0

Answer:

D. flight or flight response.

Explanation:

im 99.999999% sure im right.

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pishuonlain [190]
The answer is "B) Most species names are written in Swedish because Linnaeus was Swedish." Actually most if not all names in the Modern System of Taxonomic Classification are in Latin. 
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4 years ago
Physical Science AIS - AE 20-21-Kotal / Unit 2: Reactions and Radioactivity / The Environment
astraxan [27]

Answer:19

Explanation:

6 0
3 years ago
What is the frequency of a wave that has a speed of 0.6 m/s and a wavelength of 0.020 meter?
UNO [17]
The formula for wave motion is speed of wave equals frequency times wavelength.v = f lambdarearrangingf = v/lambdaf = 0.6/0.02 = 60/2 = 30Hz, or cycles per second.
7 0
3 years ago
A laser beam of wavelength λ=632.8 nm shines at normal incidence on the reflective side of a compact disc. The tracks of tiny pi
Juliette [100K]

To solve this problem we will apply the concepts given by the principles of superposition, specifically those described by Bragg's law in constructive interference.

Mathematically this relationship is given as

dsin\theta = n\lambda

Where,

d = Distance between slits

\lambda = Wavelength

n = Any integer which represent the number of repetition of the spectrum

\theta = sin^{-1} (\frac{n\lambda}{d})

Calculating the value for n, we have

n = 1

\theta_1 = sin^{-1} (\frac{\lambda}{d})\\\theta_1 = sin^{-1} (\frac{632.8*10^{-9}}{1.6*10^{-6}})\\\theta_1 = 23.3\°

n=2

\theta_2 = sin^{-1} (\frac{2\lambda}{d})\\\theta_2 = sin^{-1} (2\frac{632.8*10^{-9}}{1.6*10^{-6}})\\\theta_2 = 52.28\°

n =3

\theta_2 = sin^{-1} (\frac{2\lambda}{d})\\\theta_2 = sin^{-1} (3\frac{632.8*10^{-9}}{1.6*10^{-6}})\\\theta_2 = \text{not possible}

Therefore the intensity of light be maximum for angles 23.3° and 52.28°

7 0
4 years ago
A cylindrical tube sustains standing waves at the following frequencies: 600 Hz, 800 Hz, and 1000 Hz. The tube does not sustain
Thepotemich [5.8K]

Answer:

Explanation:

In  closed organ pipe notes with odd harmonics are produced and in open organ pipe notes with all odd and even harmonics are produced. notes with frequencies 600, 800 and 1000 Hz are produced. These are 3 , 4 and 5 times 200 Hz. ie both odd and even times of 200 . So fundamental frequency appears to be 200 Hz. There is no note available between 800 and 1000. It also indicates that 200 Hz is the fundamental frequency and the pipe is open at both ends.

3 0
3 years ago
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