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lana66690 [7]
2 years ago
5

11,12,13,14 please...

Chemistry
1 answer:
jekas [21]2 years ago
5 0
11. D
12.C
13. For 13 i would say B but not so sure
14. A
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If 224 g of iron reacts with oxygen, forming
Likurg_2 [28]

Answer: 208g

Explanation: Since 224 grams produces 96 grams more, then 112 grams will produce 208 grams.

8 0
3 years ago
If the density of a certain spherical atomic nucleus is 1.0 _ 1014 g cm_3 and its mass is 2.0 _ 10_23 g, what is its radius in c
melamori03 [73]
1) Calculate the volume from d = m/V => V = m/d = 2.0*10^-23 g /  1.0*10^14 g/cm^3 = 2.0*10^-9 cm^3

2) Now use the formula of volume for a sphere: V = (4/3)π(r^3) =>

r =∛[3V/(4π)] = ∛[(3*2.0*10^-9 cm^3) / (4π)] = 0.48*10^-3 cm = 4.8*10^-4 cm = 0.00048cm
5 0
3 years ago
A sample of 0.300 mol of a metal m reacts completely with excess fluorine to form 23.4 g of mf2. what element is represented by
Phoenix [80]

Molecular weight of m is 40g. Hence, name of element m is Calcium. which is represented by the symbol Ca.

Given,

Moles of metal M = 0.300 moles

 weight of mF₂ formed =23.4g

we have to find the name of element m...

Now,

 m + F₂ → mF₂

1 mole of m reacts with 1 mole of F₂ (or 2 molecule of flourine) to form 1 mole of mF₂

Hence,

 0.300 moles of m reacts with 0.300 moles of F₂ to form 0.300 moles of mF₂.

 

Hence,

 23.4 g = 0.300 moles of mf2

0.300 × 38g + 0.300 × m = 23.4 g

Hence

 m = 40 g

So, molecular weight of m is 40g. Hence, name of element m is Calcium. which is represented by the symbol Ca.

 Thus, from the above conclusion we can say that, name of element m is Calcium. which is represented by the symbol Ca.

Learn more about Calcium here:brainly.com/question/26636816

#SPJ4

5 0
1 year ago
Determine if each compound shown is soluble or insoluble. cu(oh)2
vredina [299]

We have to determine if the given compound is soluble or insoluble in water.

The given compound is copper (II) hydroxide, Cu(OH)_{2}. According to the solubility rules the hydroxides of all metal ions are insoluble except that of ammonium and the alkali metal ions. So copper(II) hydroxide will be insoluble in water. In aqueous solution, copper (II) hydroxide would exist as a sparingly soluble compound in which the undissociated compound remains in equilibrium with the ions Cu^{2+}and OH^{-}. The equilibrium would remain mostly towards undissociated form.

Cu(OH)_{2}(s)Cu^{2+}(aq)+2OH^{-}(aq)

Therefore, Cu(OH)_{2}is insoluble in water.

4 0
3 years ago
I have 2 hours to turn this in and i have no idea how to do this please help
Aleks [24]
Idk either so good luck
3 0
3 years ago
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