Answer:
Ein: 2.75*10^-3 N/C
Explanation:
The induced electric field can be calculated by using the following path integral:
Where:
dl: diferencial of circumference of the ring
circumference of the ring = 2πr = 2π(5.00/2)=15.70cm = 0.157 m
ФB: magnetic flux = AB (A: area of the loop = πr^2 = 1.96*10^-3 m^2)
The electric field is always parallel to the dl vector. Then you have:
Next, you take into account that the area of the ring is constant and that dB/dt = - 0.220T/s. Thus, you obtain:
hence, the induced electric field is 2.75*10^-3 N/C
Without friction, Newton's second law, in the form F=ma would apply.100=50a. So the acceleration should be 2m/s^2100-friction = 50x1.5100-friction = 75100-75=friction25N = friction
Answer:
Explanation:
The problem is based on vibration in string .For it the formula is as follows :
n = k √T , n is frequency of fundamental tone , k is constant for a string of given length and T is tension in the string .
In the first case weight of sphere is equal to tension .
weight = volume of sphere x density of copper x g
= v x 8960 x g
Putting the values
300 = k √ (v x 8960 x g)
300 = k √ 87808v
When the sphere is half submerged
tension is equal to apparent weight of sphere in water
= v x 8960 x g - .5 v x 1000 x 9.8 , v is volume
= 82908v
for second case
n = k √ 82908v
dividing the two equations
n / 300 =
= .9716
n = 291.5 Hz .
The answer is
D. in a straightforward, objective manner
A. It is the strongest force possible.
Explanation:
The force exerted on a charged particle moving in a region with a magnetic field is given by the following equation:
where
q is the magnitude of the charge
v is the velocity of the particle
B is the strength of the magnetic field
is the angle between the direction of the velocity and of the field
From the equation, we notice that:
- The force is maximum when the particle is moving perpendicular to the magnetic field, therefore when and
- The force is zero when the particle is moving parallel (or anti-parallel) to the magnetic field, therefore when and
Based on these observation, we can immediately conclude that the only correct option among the given choices is
A. It is the strongest force possible.
Learn more about magnetic fields:
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