Answer:
0.44g
Explanation:
Given parameters:
Mass of magnesium hydroxide = 0.645g
Solution
The balanced reaction equation is shown below:
Mg(OH)₂ → MgO + H₂O
From the equation above, we see that the number of atoms are conserved.
To find the mass of magnesium oxide produced, we find the number moles of the decomposed magnesium hydroxide first:
Molar mass of Mg(OH)₂ = 24 + 2(16+1) = 58g/mol
Number of moles of Mg(OH)₂ = 
= 
= 0.011mole
Now, from the balanced equaiton, we know that:
1 mole of Mg(OH)₂ produces 1 mole of MgO
Therefore, 0.011mole of Mg(OH)₂ will produce 0.011mole of MgO
so mass of MgO = number of moles of MgO x molar mass of MgO
Molar mass of MgO = 24 + 16 = 40g/mol
mass of MgO = 0.011 x 40 = 0.44g
Answer:
<em>It is a method used to identify a suspect.</em>
Explanation:
<em>DNA fingerprinting is a method used to identify an individual from a sample of DNA by looking at unique patterns in their DNA.</em>
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Answer:
- Compress
- Fixed
- Melts
- Melting Point
- Freezing Point
- High
- Crystalline
- Lattice
- Unit cell
- Amorphous solids
Explanation:
Solids tend to be dense and difficult to <u>compress.</u>
They do not flow or take the shape of their containers, like liquids do, because the particles in solids vibrate around <u>fixed</u> points.
When a solid is heated until its particles vibrate so rapidly that they are no longer held in fixed positions, the solid <u>melts</u>.
<u>Melting point</u> is the temperature at which a solid changes to a liquid. The melting and <u>freezing point</u> of a substance are at the same temperature.
In general, ionic solids tend to have relatively <u>high</u> melting points, while molecular solids tend to have relatively low melting points.
Most solids are <u>crystalline</u>
The particles are arranged in a pattern known as a crystal <u>lattice</u>
The smallest subunit of a crystal lattice is the <u>unit cell</u>
Some solids lack an ordered internal structure and are called <u>amorphous solids.</u>
Answer:
38.4 atm
Explanation:
Data obtained from the question include:
V1 (initial volume) = 3200 L
P1 (initial pressure) = 3.00 atm
V2 (final volume) = 250.0 L
P2 (final pressure) = ?
Using Boyle's law equation P1V1 = P2V2, the final pressure can be obtained as follow:
P1V1 = P2V2
3 x 3200 = P2 x 250
Divide both side by 250
P2 = 3 x 3200/250
P2 = 38.4 atm
Therefore, the pressure of the gas if ethylene is supplied by a 250.0 L tank is 38.4 atm
The Orbital configuration for Manganese is as follows:
1s2 2s2 2p6 3s2 3p6 4s2 3d5
It says 3d is shown with five orbitals- this is correct
Then it says the first two orbitals have two electrons-this is incorrect.
When filling in the orbitals for any element, you first need to distribute to ALL orbitals then extras go from there.
The orbital d can have up to 10 electrons so you need to distribute at least one electron to all ten. Since you only have 5 then only 5 orbitals would have electrons in them. In order for ANY of the orbitals to have two electrons, there would need to be AT LEAST 11 electrons to distribute.
