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MatroZZZ [7]
2 years ago
11

What is the water vapor density maximum at 30 ᵒC? *

Chemistry
1 answer:
riadik2000 [5.3K]2 years ago
8 0

2.3 mol/1000L

Explanation:

relative humidity (rh)is the ratio of the partial pressure of water at a given temprature

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The enthalpy change for converting 10.0 g of ice at -25.0 °C to water at 90.0 °C is __________ kJ. The specific heats of ice, wa
Nina [5.8K]
AH1 = m * c1 * AT1 calculate this for ice (-25C to 0C) AH2 = AHfus(1 mole)=6.01 kJ = 6010 J AH3 = m *c3 * AT3 calculat this for water (0C to 100C) AH4 = AHvap(1mole)=40.67 kJ = 40670 J AH5= m * c5 * AT5 calculate this for steam (100C to 125C) 
Sum ---- AH1+AH2+AH3+AH4+AH5 
Data m=18g (1mole water) 
c1=specific heat ice= 2.09 J/g K c3=specific heat water= 4.18 J/g K c5=specific heat steam= 1.84 J/g K 
AT = (Tend - Tinitial) as this is a difference between temperatures it doesn't matter the units Celsius or Kelvin. Kelvin (K)=Celsius (C)+273.15 
AT1 = 0C - (-25C)= 25C= 273.15K - 248.15K= 25K AT3= 100C - 0C = 100C= 100K AT5= 125C - 100C= 25C=25K
6 0
3 years ago
How do you do double replacement reactions?
Harman [31]
You have to switch the elements based in if they're metals/nonmetals. so nonmetals switch with each other and metals switch with each other.

AB + CD ---> AC + BD
5 0
3 years ago
10. (2 points) What is the process by which a solute forms a solution in a solvent. A) calisthenics B) bumping C) dissolution D)
Triss [41]

Answer: (C) Dissolution is the process by which a solute form a solution in a solvent.

Explanation: Dissolution can be described as the process by which a solute dissolves in a solvent to give a solvent.

The solute may be a solid, liquid or gas and solvent is usually a liquid but can also be liquid, gas or supercritical fluid. The most common solvent is water and it is referred to as the universal solvent.

Example are:

1.Stirring of sugar in water.

In this case the solute is the sugar and the solvent is water.

2.Organic substances dissolves readily in solvent like kerosene and benzene and they are known as non-polar solvent while the organic substances are the solute

4 0
3 years ago
A 2.1−mL volume of seawater contains about 4.0 × 10−10 g of gold. The total volume of ocean water is about 1.5 × 1021 L. Calcula
Fiesta28 [93]

Answer:

Total worth of gold in the ocean = $5,840,000,000,000,000

Explanation:

As stated in the question above, 4.0 x 10^-10 g of gold was present in 2.1mL of ocean water.

Therefore, In 1 L of ocean water there will be,

(4.0 x 10^-10)/0.0021

= 1.9045 x 10^-7 g of gold per Liter of ocean water.

So in 1.5 x 10^-21 L of ocean water, there will be

(1.9045 x 10^-7) * (1.5 x 10^-21)

= 2.857 x 10^14 g of gold in the ocean.

1 gram of gold costs $20.44, that is 20.44 dollars/gram. The total cost of the gold present in the ocean is

20.44 * (2.857 x 10^14)

= $5,840,000,000,000,000

8 0
3 years ago
Give the answer to the problem below using the correct number of significant digits. (1.3 x 103) x (5.724 x 104)
Gemiola [76]
(133.9) x (595.296)= 79,710.1344
Answer with significant digits: 80,000
1.3 has two significant digits so 79,700 rounds up to 80000.
6 0
3 years ago
Read 2 more answers
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