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3 years ago

Please help!! any inappropriate answers will be reported

1 answer:

6 0

When the total surface area of the solute particles is increased, the solute dissolves more rapidly. Breaking a solute into smaller pieces increases its surface area and increases its rate of solution. So, any answer with “as surface area increases, solid dissolves faster” would be correct. :)

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O que acontece com a perspiração celular se, pro algum motivo, uma pessoa foi impedida de executar a respiração pulmonar?

12345 [234]

Answer:

I wish I spoke this languge.

Explanation:

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3 years ago

Gram The Moon was once much doser to E ffect do you think that this distance had What on eclipses?

grin007 [14]

I think the sun would've seem bigger than the moon.

7 0

4 years ago

Calculate the standard enthalpy change for the reaction at 25 ∘ C. Standard enthalpy of formation values can be found in this li

Anastasy [175]

Answer:

-179.06 kJ

Explanation:

Let's consider the following balanced reaction.

HCl(g) + NaOH(s) ⟶ NaCl(s) + H₂O(l)

We can calculate the standard enthalpy change for the reaction (ΔH°r) using the following expression.

ΔH°r = 1 mol × ΔH°f(NaCl(s)) + 1 mol × ΔH°f(H₂O(l)) - 1 mol × ΔH°f(HCl(g)) - 1 mol × ΔH°f(NaOH(s))

ΔH°r = 1 mol × (-411.15 kJ/mol) + 1 mol × (-285.83 kJ/mol) - 1 mol × (-92.31 kJ/mol) - 1 mol × (-425.61 kJ/mol)

ΔH°r = -179.06 kJ

7 0

3 years ago

Select the correct answer.

Step2247 [10]

Answer:

Vanadium(V) oxide is the inorganic compound with the formula V2O5. Commonly known as vanadium pentoxide,

Explanation:

then it is answer D

5 0

3 years ago

A sample of cesium carbonate, weighing 3.80 g, requires 1.90 g of hydrogen bromide gas to completely decompose to water, cesium

vladimir1956 [14]

Answer:

Choice A. 0.50 g.

Explanation:

According to the question, the reaction here converts

caesium (cesium) carbonate and
hydrogen bromide

cesium bromide,
carbon dioxide, and
water.

By the Law of Conservation of Mass, matter can neither be created nor destroyed in a chemical reaction. (Shrestha et. al, Introductory & GOB Chemistry, Chemistry Libretexts, 2019.)

In other words, the mass of the reactants, combined, shall be the same as the mass of the products, combined.

What's the mass of the reactants?

$\rm \underbrace{\rm 3.80\;g}_{\mathrm{Cs_2CO_3}} + \underbrace{\rm 1.90\; g}_{\mathrm{HBr}} = 5.70\;g$ .

What's the mass of the products?

Let $m(\mathrm{CO_2})$ represent the mass of carbon dioxide produced in this reaction.

The mass of the products will be:

$\rm \underbrace{\rm 5.20\;g}_{\mathrm{CeBr}\text{ and }\mathrm{H_2O}} + \underbrace{m(\mathrm{CO_2})}_{\mathrm{CO_2}}$ .

The two masses shall be equal. That is:

$\rm 5.20\; g + \mathnormal{m}(\mathrm{CO_2}) = 5.70\;g$ .

$m(\mathrm{CO_2}) = \rm 0.50\;g$ .

In other words, by the Law of Conservation of Mass, the mass of carbon dioxide produced in this reaction will be $\rm 0.50\;g$ .

8 0

4 years ago