Answer:
2.06 m/s
Explanation:
From the law of conservation of linear momentum, the sum of momentum before and after collision are equal. Considering this case where we have frictionless surface, no momentum is lost in the process.
Momentum before collision
Momentum is given by p=mv where m and v represent mass. The initial sum of momentum will be 9v+(27*0.5)=9v+13.5
Momentum after collision
The momentum after collision will be given by (9+27)*0.9=32.4
Relating the two then 9v+13.5=32.4
9v=18.5
V=2.055555555555555555555555555555555555555 m/s
Rounded off, v is approximately 2.06 m/s
Crust sitting on top of Milton rock of the mantle
If the radius of the cylinder is halved and length is kept unchanged then the density of air inside the cylinder will increase.
As it can be said that density is inversely proportion to the square of the radius.
Density of Cylinder
Density is the ratio of mass to volume.
The formula for density is: ρ= m/v.
The formula for the Mean Density of a cylinder is:
ρ= m/ (π•r²•h)
where:
ρ is the density of the cylinder
m is the mass of the cylinder
h is the height of the cylinder
So, with increase in radius the of the cylinder there is decrease in the density of cylinder.
And on decreasing the radius of the cylinder there is increase in the density of the cylinder.
As it can be said that density is inversely proportion to the square of the radius.
To learn more about Density Of Cylinder
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If the velocity is decreased by half, then Kinetic energy will reduced to it's 4 times,
= 1.9 * 10³ / 4
= 4.75 * 10²
In short, Your Answer would be Option B
Hope this helps!
