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katrin2010 [14]
3 years ago
8

A small pond contains 8 catfish and two bluegill. If eight fish are caught at random what is the probability that all of them ar

e catfish
Mathematics
1 answer:
blagie [28]3 years ago
5 0
There is a high probability of all of them being catfish since there are 8 catfish in total and since 8 were randomly caught. I don’t truly know.
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In the parking lot shown, the lines
jolli1 [7]
22 is the answer because I just did it
8 0
4 years ago
PLS HELP ME I NEED IT
OLEGan [10]

Step-by-step explanation:

the area = (\frac{1}{2}) (18)(4)\\ = 36ft^{2}

please give me a brainliest answer

8 0
3 years ago
A gambler claims that horses in a horse race that start closer to the rail have an advantage over horses that start further from
k0ka [10]

Answer:

Hence, the p-value ( 0.699986) > 0.05,  FAIL TO REJECT THE NULL HYPOTHESIS

there is no significant evidence that starting position is a factor in horse races

Step-by-step explanation:

Given the data in the question;

Starting position:     1     2     3     4     5     6

# of Winners:         25   22   18   19    21   15

Mean x" (E) = (25+22+18+19+21+15)/6 = 120/6 = 20

Observed/Expected value table;

O       E            ((O-E)²) / E

25    20            1.25

22    20            0.2

18     20            0.2

19     20           0.05

21     20           0.05

15     20           1.25

∑                         3

so using chi square = ∑(((O-E)²) / E) = 3

DF = n-1 = 6-1 = 5

then, the critical chi square value is;

significance level = 0.05

chi square( critical ) = 11.07049769

from table;

p - value = 0.699986

Hence, the p-value ( 0.699986) > 0.05,  FAIL TO REJECT THE NULL HYPOTHESIS

there is no significant evidence that starting position is a factor in horse races

8 0
3 years ago
Question 1
Damm [24]

Answer: i think its B

Step-by-step explanation:

4 0
3 years ago
A regular hexagon is formed by six equilateral triangles this makes it somewhat easy to find the area of the hexagon using the p
frozen [14]
1/2 of the side length p= 1/2 x 4 =2
centre angle=360/6=60 degrees

The APOTHEM bisects or divides the centre angle into two equal angles
1/2 of the centre angle=60/2=30 degrees
tan 30 degrees = 2/APOTHEM
APOTHEM=2/tan 30= 3.46 cm

The APOTHEM is the perpendicular height of the equilateral triangle given in the diagram.
Area of the equilateral triangle
=1/2 x 4 x 3.46
=6.93 cm^2
Area of the regular hexagon= 6 x area of the equilateral triangle= 6 x 6.93 =41.6 cm^2

Hope this helps!
4 0
3 years ago
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