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4 years ago

Draw the vector C⃗ =A⃗ +2B⃗ .

Physics

1 answer:

spin [16.1K]4 years ago

4 0

Answer:

A) C is 2 units towards right

B) C is 9 units towards right and 3 units towards up

C) C is 4 units towards right and 1 unit towards down

Explanation:

Drawings are given in the attachment.

A)Since,

A is 4 units towards right,

B is 1 unit towards left,

Then,

C is 2 units towards right.

B) Since,

A is 4 units towards right and 2 units towards up,

B is 1 unit towards left,

Then,

C is 9 units towards right and 3 units towards up.

C) Since,

A is 4 units towards right and 2 units towards up,

B is 1 unit towards right, and 1 unit towards down

Then,

C is 4 units towards right and 1 unit towards down.

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Whose geocentric model was accepted for 1400 years

zysi [14]

IDK the answer but I think it was "Ptolemy" whose geocentric model of the solar system was accepted for 1,400 years, and was embraced by the the Church until Galileo called it into question.

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4 years ago

Calculate the lowest energy (in ev) for an electron in an infinite well having a width of 0.050 mm.

MA_775_DIABLO [31]

The lowest energy of electron in an infinite well is 1.2*10^-33J.

To find the answer, we have to know more about the infinite well.

<h3>What is the lowest energy of electron in an infinite well?</h3>

It is given that, the infinite well having a width of 0.050 mm.
We have the expression for energy of electron in an infinite well as,

$E_n=\frac{n^2h^2}{8mL^2}$

where;

$m=9.1*10^{-31}kg\\L=0.050*10^{-3}m\\h=6.63*10^{-34}Js\\n=1$

Thus, the lowest energy of electron in an infinite well is,

$E_1=\frac{(6.63*10^{-34})^2}{8*9.1*10^{-31}*(0.050*10^{-3})}=1.2*10^{-33}J$

Thus, we can conclude that, the lowest energy of electron in an infinite well is 1.2*10^-33J.

Learn more about the infinite well here:

brainly.com/question/20317353

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7 0

1 year ago

Use Snell's Law to solve the following:

azamat

Answer:

1.171

Explanation:

if n₁sinΘ₁=n₂sinΘ₂, then n₂=n₁sinΘ₁ / sinΘ₂;

$n_2=\frac{1.5*sin45}{sin65}=\frac{1.5*0.707}{0.906} =1.1705$

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3 years ago

A 5 newton force and a 7 newton force act concurrently on a point. As the angle between the forces is increased from 0 to 180 th

Reika [66]

Answer:

The magnitude of the resultant decreases from A+B to A-B

Explanation:

The magnitude of the resultant of two vectors is given by

$R=\sqrt{A^2 +B^2 +2AB cos \theta}$

where

A is the magnitude of the first vector

B is the magnitude of the second vector

$\theta$ is the angle between the directions of the two vectors

In the formula, A and B are constant, so the behaviour depends only on the function $cos \theta$ . The value of $cos \theta$ are:

- 1 (maximum) when the angle is 0, so the magnitude of the resultant in this case is

$R=\sqrt{A^2 +B^2+2AB}=\sqrt{(A+B)^2}=A+B$

- then it decreases, until it becomes 0 when the angle is 90 degrees, where the magnitude of the resultant is

$R=\sqrt{A^2 +B^2+0}=\sqrt{A^2+B^2}$

- then it becomes negative, and continues to decrease, until it reaches a value of -1 when the angle is 180 degrees, and the magnitude of the resultant is

$R=\sqrt{A^2 +B^2-2AB}=\sqrt{(A-B)^2}=A-B$

4 0

3 years ago

If the cross-section of a wire of fixed length is doubled, how does the resistance of that wire change? (this is for studying fo

Ymorist [56]

If the cross-section of a wire of fixed length is doubled, the resistance of that wire change into doubled.We know that the total length of the wires will affect the amount of resistance. The longer the wire, the more resistance that there will be so the answer is doubled.

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3 years ago